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Sholpan [36]
3 years ago
11

Please help me with this question

Physics
1 answer:
padilas [110]3 years ago
7 0
This makes no sense thought. What is the question asking?

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Please help AFAP........................
andriy [413]

Answer:

afap

Explanation:

4 0
3 years ago
A paper-filled capacitor is charged to a potential difference of V 0 = 2.5 V V0=2.5 V . The dielectric constant of paper is κ =
forsale [732]

Answer:

V_1=9.25 V

Explanation:

We are given that

V_0=2.5 V

k=3.7

We have to find the new potential difference of the capacitor.

When the capacitor is disconnected then the charge stored in capacitor is constant.

When we introduce material of dielectric constant k between the plates of capacitor then the capacitance of capacitor increases k times.

C_0=\frac{Q}{V_0}

C'=kC=\frac{kQ}{V_1}

\frac{Q}{V_0}=\frac{kQ}{V_1}

V_0=\frac{V_1}{k}

Using the formula

V_0=\frac{V_1}{k}

V_1=V_0k=2.5\times 3.7=9.25 V

Hence, the new potential difference V_1=9.25 V

5 0
3 years ago
It took 50 joules to push a shopping cart 5 meters.with what face was the shopping cart pushed?
gladu [14]
Hello! So Ik this can be wrong but I worked hard for it(: It took 50 joules to push a shopping cart 5 meters with what force was the shopping cart pushed. blinded him to enable him and his men to escape. the answer is: round. Done!
4 0
3 years ago
A hotel elevator ascends 200m with maximum speed of 5m/s. Its acceleration and deceleration both have a magnitude of 1.0m/s2. Pa
ValentinkaMS [17]

Answer:

45 s .

Explanation:

The accelerator will first accelerate , then move with uniform velocity and at last it will decelerate to rest .

displacement s = ?

acceleration a = 1 m /s²

Final speed v = 5 m/s

initial speed u = 0

v² = u² + 2as

5² = 0 + 2 x 1 x s

s = 12.5  m

B)  Let time of acceleration or deceleration be t

v = u + a t

5 = 0 + 1 t

t = 5 s

Similarly displacement during deceleration = 12.5 m

Total distance during uniform motion = 200 - ( 12.5 + 12.5 ) =  175 m .

velocity of uniform motion = 5 m /s

time during which there was uniform velocity = 175 / 5 = 35 s

Total time = 5 + 35 + 5 = 45 s .

4 0
3 years ago
3 Below, someone is trying to balance a plank with
belka [17]

Answer:

a. The moment of the 4 N force is 16 N·m clockwise

b. The moment of the 6 N force is 12 N·m anticlockwise

Explanation:

In the figure, we have;

The distance from the point 'O', to the 6 N force = 2 m

The position of the 6 N force relative to the point 'O' = To the left of 'O'

The distance from the point 'O', to the 4 N force = 4 m

The position of the 4 N force relative to the point 'O' = To the right of 'O'

a. The moment of a force about a point, M = The force, F × The perpendicular distance of the force from the point

a. The moment of the 4 N force = 4 N × 4 m = 16 N·m clockwise

b. The moment of the 6 N force = 6 N × 2 m = 12 N·m anticlockwise.

8 0
3 years ago
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