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lesantik [10]
4 years ago
13

Multiply r^2+7r+10/3 by 3r-30/r^2-5r-50

Mathematics
1 answer:
olga_2 [115]4 years ago
5 0
<span>(r^2+7r+10/3) * (3r-30/r^2-5r-50)
1/3(3r^2+21r+10) x 3(r-10)/(r^2-5r-50)
(3r^2+21r+10)x(r-10)/(r^2-10r+5r-50)
(3r^2+21r+10)x(r-10)/(r-10)(r+5)
3r^2+21r+10/(r+5)



</span>
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