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ahrayia [7]
3 years ago
6

Which type of formula represents the simplest whole-number ratio of atoms of the elements in a compound?

Chemistry
1 answer:
sleet_krkn [62]3 years ago
5 0
The empirical formula represents the simplest whole number shows the simplest whole number ratio of atoms in a compound.  An example of this is the empirical formula for glucose (C₆H₁₂O₆) is C₃H₆O₃.  

I hope this helps.  Let me know if anything is unclear.
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Which of these structures are found in both plant and animal cells
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Answer: B

Explanation: The mitochondria are vacuoles and ribosomes are in both plant and animal cell

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3 years ago
what is the balanced equation for the reaction of solid magnesium metal with oxygen gas to produce solid magnesium oxide
GaryK [48]

Answer:

2Mg + O₂ ⟶ 2MgO

Explanation:

Step 1. Start with the most complicated-looking formula (O₂?).

Put a 1 in front of it.

Mg + 1O₂ ⟶ MgO

Step 2. Balance O.

We have fixed 2 O on the left. We need 2O on the right. Put a 2 in front of MgO.

Mg + 1O₂ ⟶ 2MgO

Step 3. Balance Mg.

We have fixed 2 Mg on the right-hand side. We need 2 Mg atoms on the left. Put a 2 in front of Mg.

2Mg + 1O₂ ⟶ 2MgO

Every formula now has a coefficient. The equation should be balanced. Let’s check.

<u>Atom</u>  <u>On the left</u>  <u>On the righ</u>t

  Mg             2                  2

  O                2                  2

All atoms are balanced.

The balanced equation is

2Mg + O₂ ⟶ 2MgO

4 0
3 years ago
What is the entropy of a solid based on
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The answer is:

The arrangement of the Atoms
4 0
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The half-life of the first-order decay of radioac- . 14C . b l:Ive 1s a out 5720 years. Calculate the rate constant for the reac
Alinara [238K]

Answer:

a. Rate constant: 1.2118x10⁻⁴ yrs⁻¹

b. The age of the object is 20750 years

Explanation:

a. We can solve the rate constant in an isotope decay by using Half-Life, as follows:

K = Ln 2 / Half-life

K = ln 2 / 5720 years =

<h3>1.2118x10⁻⁴ yrs⁻¹</h3><h3 />

b. The general equation of isotope decay is:

Ln [A] = -kt + Ln [A]₀

<em>Where [A] is concentration of the isotope after time t, </em>

<em>k is rate constant</em>

<em>and [A]₀ initial concentration of the isotope.</em>

<em />

Computing the values of the problem:

Ln [0.89x10⁻¹⁴] = -1.2118x10⁻⁴ yrs⁻¹t + Ln [1.1x10⁻¹³]

-2.5144 = -1.2118x10⁻⁴ yrs⁻¹t

20750 years = t

The age of the object is 20750 years

<em />

4 0
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anastassius [24]

Explanation:

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