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ehidna [41]
3 years ago
10

ΑC2H6O+βO2 → γC2H4O2+δH2O

Chemistry
1 answer:
olga2289 [7]3 years ago
4 0
Balancing the equation, we get:

2C₂H₆O + O₂ → 2C₂H₄O₂ + 2H₂O

So 
α = 2
β = 1
γ = 2
δ = 2
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What is the correct name for HCIO3
Arada [10]
The answer is chloric acid. Hope this helps!
7 0
3 years ago
Read 2 more answers
The first ionization energy of bismuth is ei1 = +703 kj/mol. what is the longest possible wavelength of light that could ionize
Marianna [84]

Hey there!:

Given, energy, E = 703 kJ/mol


λ = ?


We need to do conversion of kJ/mol to J


So, E = 703 kJ/mol*1000 J*kJ *1 mole / 6.023*10²³

 = 1.17*10-18 J

We know formula,


E = h*C/ λ


So, λ = h*C / E


=  ( 6.626*10-34 J.s ) *  ( 3.0*10⁸ m.s⁻¹ ) /  ( 1.17*10⁻¹⁸ J )


= 1.70*10⁻⁷ m


So, 1 m = 1*10⁹ nm


So, 1.70*10⁻⁷ m = ?


= 170 nm

Hope that helps!

7 0
3 years ago
Calculate the mass of water produced when 7.26 g of butane reacts with excess oxygen
MaRussiya [10]

Answer:

11.3 g.

Explanation:

Hello there!

In this case, since the combustion of butane is:

C_4H_{10}+\frac{13}{2} O_2\rightarrow 4CO_2+5H_2O

Thus, since there is a 1:5 mole ratio between butane and water, we obtain the following mass of water:

m_{H_2O}=7.26gC_4H_{10}*\frac{1molC_4H_{10}}{58.14gC_4H_{10}}*\frac{5molH_2O}{1molC_4H_{10}}  *\frac{18.02gH_2O}{1molH_2O}

Therefore, the resulting mass of water is:

m_{H_2O}=11.3gH_2O

Best regards!

4 0
3 years ago
When 21.45 g of KNO3 was dissolved in water in a calorimeter, the temperature fell from 25.00°C to 14.14 °C. If the heat capacit
pashok25 [27]

25.9 kJ/mol. (3 sig. fig. as in the heat capacity.)

<h3>Explanation</h3>

The process:

\text{KNO}_3\;(s) \to \text{KNO}_3\;(aq).

How many moles of this process?

Relative atomic mass from a modern periodic table:

  • K: 39.098;
  • N: 14.007;
  • O: 15.999.

Molar mass of \text{KNO}_3:

M(\text{KNO}_3) = 39.098 + 14.007 + 3\times 15.999 = 101.102\;\text{g}\cdot\text{mol}^{-1}.

Number of moles of the process = Number of moles of \text{KNO}_3 dissolved:

\displaystyle n = \frac{m}{M} = \frac{21.45}{101.102} = 0.212162\;\text{mol}.

What's the enthalpy change of this process?

Q = C\cdot \Delta T = 0.505 \times (25.00 - 14.14) = 5.4843\;\text{kJ} for 0.212162\;\text{mol}. By convention, the enthalpy change \Delta H measures the energy change for each mole of a process.

\displaystyle \Delta H = \frac{Q}{n} = \frac{5.4843\text{kJ}}{0.212162\;\text{mol}} = 25.8\;\text{kJ}\cdot\text{mol}^{-1}.

The heat capacity is the least accurate number in these calculation. It comes with three significant figures. As a result, round the final result to three significant figures. However, make sure you keep at least one additional figure to minimize the risk of rounding errors during the calculation.

4 0
3 years ago
Calculate the molarity of a solution containing 9.25 mol H2SO4 in 2.75 L of solution.
Akimi4 [234]

Answer:

THE MOLARITY OF THE SOLUTION IS 3.36 MOLE/L

Explanation:

First we must understand what molarity is.

Molarity is the number of mole per unit volume of solution. In this question, 9.25 mole of H2SO4 was given in 2.75 L of solution.

Molarity is written in mole per dm3 or L.

So we can calculate the molarity:

9.25  ole of H2SO4 = 2.75 L of solution

The number of mole in 1 L of solution will be:

= 9.25 mole / 2.75 L

= 3.3636 mole/ L

In conclusion, the molarity of the solution is approximately 3.36 mole/L

8 0
4 years ago
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