The answer is chloric acid. Hope this helps!
Hey there!:
Given, energy, E = 703 kJ/mol
λ = ?
We need to do conversion of kJ/mol to J
So, E = 703 kJ/mol*1000 J*kJ *1 mole / 6.023*10²³
= 1.17*10-18 J
We know formula,
E = h*C/ λ
So, λ = h*C / E
= ( 6.626*10-34 J.s ) * ( 3.0*10⁸ m.s⁻¹ ) / ( 1.17*10⁻¹⁸ J )
= 1.70*10⁻⁷ m
So, 1 m = 1*10⁹ nm
So, 1.70*10⁻⁷ m = ?
= 170 nm
Hope that helps!
Answer:
11.3 g.
Explanation:
Hello there!
In this case, since the combustion of butane is:

Thus, since there is a 1:5 mole ratio between butane and water, we obtain the following mass of water:

Therefore, the resulting mass of water is:

Best regards!
25.9 kJ/mol. (3 sig. fig. as in the heat capacity.)
<h3>Explanation</h3>
The process:
.
How many moles of this process?
Relative atomic mass from a modern periodic table:
- K: 39.098;
- N: 14.007;
- O: 15.999.
Molar mass of
:
.
Number of moles of the process = Number of moles of
dissolved:
.
What's the enthalpy change of this process?
for
. By convention, the enthalpy change
measures the energy change for each mole of a process.
.
The heat capacity is the least accurate number in these calculation. It comes with three significant figures. As a result, round the final result to three significant figures. However, make sure you keep at least one additional figure to minimize the risk of rounding errors during the calculation.
Answer:
THE MOLARITY OF THE SOLUTION IS 3.36 MOLE/L
Explanation:
First we must understand what molarity is.
Molarity is the number of mole per unit volume of solution. In this question, 9.25 mole of H2SO4 was given in 2.75 L of solution.
Molarity is written in mole per dm3 or L.
So we can calculate the molarity:
9.25 ole of H2SO4 = 2.75 L of solution
The number of mole in 1 L of solution will be:
= 9.25 mole / 2.75 L
= 3.3636 mole/ L
In conclusion, the molarity of the solution is approximately 3.36 mole/L