Answer:
Thus, the pollutant concentration in lake will be reduced to 0.2% after 6.931471 days
Explanation:
From the information given:
A(t) = amount of pollutant for time (t)
A 4 billion cubic ft is the same as 4000 million cubic ft:
∴
The Initial amount of pollutant is
However;
the pollutant rate (input) = 400 × 0 = 0
the pollutant rate (output) =
The net rate =
A(0) = 16
A(t) = 8
Answer:
25.6mL NaOH
Explanation:
We are given the Molarity of the solution () and the volume of the solution (.02L).
By multiplying the two together, we can find the moles of solution that are reacted with HCl.
This gives us .0082 moles of HCl.
We then find the moles of NaOH that are needed to react with the HCl using the equation.
As HCl and NaCl have a 1:1 ratio, we need .0082 mol of NaOH.
Dividing this value by the Molarity of the solution
Gives us the answer, in Liters (.0256), which we can then divide by 100 convert to mL.
Answer:
The reaction is not at equilibrium and reaction must run in forward direction.
Explanation:
At the given interval, concentration of NO =
Concentration of =
Concentration of NOBr =
Reaction quotient, , for this reaction =
species inside third bracket represents concentrations at the given interval.
So,
So, the reaction is not at equilibrium.
As therefore reaction must run in forward direction to increase and make it equal to .
Explanation:
The given data is as follows.
Moles of propylene = 100 moles, = 100 J/mol K
= 300 K, = 800 K
= 2 , = 0.02
Therefore, the assumptions will be as follows.
- The given system is very well insulated.
- The work is done on the system because the given process is a compression process.
- Assume that there is no friction so, work done on the system is equal to the heat energy liberated.
= W
Putting the given values into the above formula as follows.
= W
W =
= J
= 5 MJ
Hence, this shows that a minimum of 5 MJ work needs to be done.
Since, work is very less. Hence, it will not compress the given system to 800 K and 0.02 .
A force exerted by the machine is called a Mechanical force.