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sveticcg [70]
3 years ago
8

1) The speed constant was determined for the first order decomposition of an organic compound at various temperatures:

Chemistry
1 answer:
-Dominant- [34]3 years ago
6 0

Answer:

1) Eₐ = 100.3 kJ/mol

2) k = 7.62×10⁻⁴ M⁻¹s⁻¹

Explanation:

1) Make an Arrhenius graph by plotting ln(k) on the y-axis and 1/T on the x-axis (don't forget to convert temperature to Kelvin).

The slope of the line is equal to -Eₐ/R.

-Eₐ/R = -12065

Eₐ = 100,300 J/mol

Eₐ = 100.3 kJ/mol

2) Since we know the slope of ln(k) vs 1/T is -Eₐ/R, we can say:

-Eₐ/R = (ln(k₂) − ln(k₁)) / (1/T₂ − 1/T₁)

Plug in values and solve for k:

-(108,000 J/mol) / (8.314 J/mol/K) = [ln(k) − ln(1.0×10⁻³)] / [1/(35+273.15 K) − 1/(37+273.15 K)]

-12990 = [ln(k) + 6.91] / (2.09×10⁻⁵ K⁻¹)

-0.272 = ln(k) + 6.91

ln(k) = -7.18

k = 7.62×10⁻⁴ M⁻¹s⁻¹

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Uhhh I believe it is 308 k
7 0
2 years ago
Determine if the phrases below are true for catabolic pathways only, anabolic pathways only,or can apply to both pathways, by so
Ivan

Answer:

<u>Catabolic pathways;</u>

Pathway produces more ATP than it consumes

Supplies NADH for oxidative phosphorylation

<u>Anabolic pathways only</u>:

Consumes more ATP than it produces

Can require reducing agent

<u>Both pathways;</u>

At least one enzyme is regulated

All reactions are catabolized by enzymes

One or more reactions are endergonic without ATP

Explanation:

<u>Catabolic pathways;</u>

Complete oxidation of glucose and then produces more ATP. Oxidative phosphorylation is an example of catabolic pathway.

From the given following conversions are considered as catabolic pathways.

Pathway produces more ATP than it consumes

Supplies NADH for oxidative phosphorylation

<u>Anabolic pathways:</u>

Anabolic pathways produces new molecules and it requires energy in the form of ATP for the formation of new bonds.

From the given following conversions are considered as anabolic pathways.

Consumes more ATP than it produces

Can require reducing agent.

<u>Both pathways;</u>

Metabolic pathways are occuring in the cell only few enzymes are regulate these pathways.

At least one enzyme is regulated

All reactions are catabolized by enzymes

One or more reactions are endergonic without ATP

6 0
3 years ago
I NEED HELP PLEASE ASAP!! BRAINLIEST :)
SVEN [57.7K]

Answer:

Higher

Explanation:

When an object sublimates, it goes straight from the solid to the gas phase. Since this involves heating up, the object's molecules move faster, which therefore gives it higher kinetic energy. Hope this helps!

3 0
2 years ago
The ability of sodium chloride to dissolve in water is an example of a (D, right?)
kupik [55]
D) Physical Change, I would argue, because you can reverse this change by boiling off (evaporating) the water. But there are arguments for both physical and chemical change being what occurs.

A physical change results in a change of the material's appearance, but no new chemical products result. A chemical change involves a chemical reaction, with new substances produced as a result of the change.
3 0
2 years ago
A 155g sample of copper was heated to 150.0 degrees Celsius, then placed into 250.0g water at 19.8 degrees Celsius. Calculate th
bogdanovich [222]
Once for the water and once for the copper. Set up a table that accounts for each of the variables you know, and then identify the ones you need to obtain. Give me a moment or two and I will work this out for you.

Okay, so like I said before, you will need to use the equation twice. Now, keep in mind that when the copper is placed in the water (the hot into the cold), there is a transfer of heat. This heat transfer is measured in Joules (J). So, the energy that the water gains is the same energy that the copper loses. This means that for your two equations, they can be set equal to each other, but the copper equation will have a negative sign in front to account for the energy it's losing to the water.

When set equal to each other, the equations should resemble something like this:
(cmΔt)H20 = -(cmΔt)Cu
(Cu is copper).

Remember, Δt is the final temperature minus the initial temperature (T2-T1). We are trying to find T2. Since we are submerging the copper into the water, we can assume that the final temperature at equilibrium is the same for both the copper and the water. At a thermodynamic equilibrium, there is no heat transfer because both materials are at the same temperature.

T2Cu = T2H20

Now, the algebra for this part of the problem is a bit confusing, so make sure you keep track of your variables. If done right, the algebra should work out so you have this:

T2 = ((cmT1)Cu + (cmT1)H20) / ((cm)H20 + (cm)Cu)
Insert the values for the variables. Once you plug and chug, your final answer should be
26.8 degrees Celsius.
3 0
3 years ago
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