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Ghella [55]
3 years ago
14

The density of water at 30.0 °C is 0.9956 g/mL. If the specific gravity of acetic acid is 1.040 at 30.0 °C, what is the density

of acetic acid at 30.0 °C?
Chemistry
1 answer:
mash [69]3 years ago
7 0

Answer:

The density of acetic acid at 30°C = 1.0354_g/mL

Explanation:

specific gravity of acetic acid = (Density of acetic acid at 30°C) ÷ (Density of water at 30°C)

Therefore, the density of acetic acid at 30°C = (Density of water at 30°C) × (Specific gravity of acetic acid at 30°C)

= 0.9956 g/mL × 1.040

= 1.0354_g/mL

Specific gravity, which is also known as relative density, is the ratio of the density of a substance to the density of a specified standard substance.

Generally the standard substance of to which other solid and liquid substances are compared is water which has a density of 1.0 kg per litre or 62.4 pounds/cubic foot at 4 °C (39.2 °F) while gases are normally compared with dry air, with a density of 1.29 grams/litre or 1.29 ounces/cubic foot under standard conditions of a temperature of 0 °C and one standard atmospheric pressure

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Green plants use light from the Sun to drive photosynthesis, a chemical reaction in which liquid water and carbon dioxide gas fo
san4es73 [151]

Answer:

                    1.8 moles of O₂

Explanation:

                     The balance chemical equation for said double replacement (photosynthesis) reaction is as follow;

                           6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂

According to balance chemical equation,

                 6 moles of O₂ are produced by  =  6 moles of CO₂

So,

                1.8 moles of O₂ will be produced by  =  X moles of O₂

Solving for X,

                     X =  1.8 mol × 6 mol / 6 mol

                     X =  1.8 moles of O₂

Stoichiometric problems in which moles are given and moles or other reactant or product asked are the simplest problems. One should only write the balanced chemical equation and perform above method to find the required moles.

8 0
3 years ago
Give the Unabbreviated electron configuration for barium
Shalnov [3]

Answer:

Ba: 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²

Step-by-step explanation:

Step 1. Locate barium in the Periodic Table.

It's in Period 6, Group 2: Element 56 (highlighted blue in the Periodic Table below).

Step 2. Add 54 electrons to the energy levels

You add then in the order shown in the diagram below.

The complete electron configuration is:

Ba: 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²

n =  2 +     8    +    8     +       18       +       18       +  2 = 56

8 0
4 years ago
Consider the following four pairs of molecules. You may use 1H-NMR, 13C-NMR, or IRspectroscopyto differentiate the structures, b
GREYUIT [131]

Answer:

The question is incomplete. The structures were not added to the question. Find attached of the structure and the given answer.

Explanation:

See the attached file for explanation

4 0
3 years ago
A compound is 12.7% Al, 19.7% N, and 67.6% O. Determine its emperical formula.
gizmo_the_mogwai [7]

Answer:

AlN₃O₉

Explanation:

Assume that you have 100 g of the compound.

Then you have 12.7 g Al, 19.7 g N, and 67.6 g O.

1. Calculate the <em>moles</em> of each atom

Moles of Al = 12.7 × 1/26.98 = 0.4707 mol Al

Moles of N = 19.7 × 1/14.01    =  1.406   mol N

Moles of O = 67.6 × 1/16.00  = 4.225   mol O

2. Calculate the <em>molar ratios</em>.

Al: 0.4707/0.4707 = 1

N: 1.406/0.4707    = 2.987

O: 4.225/0.4707   = 8.976

3. Determine the <em>empirical formula</em>

Round off all numbers to the closest integer.

Al: 1

N: 3

O: 9

The empirical formula is AlN₃O₉.

3 0
4 years ago
Why is pluto classified as a dwarf planet?
Julli [10]

Answer:

pluto is considered a dwarf planet because it did not meet the three criteria the IAU uses to define a full sized planet

Explanation:

5 0
3 years ago
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