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Ede4ka [16]
3 years ago
11

A biologist working in a lab adds a compound to a solution that contains an enzyme and substrate. This particular compound binds

reversibly to the enzyme at the active site. Once the compound is bound to the enzyme, the rate of catalysis of substrate to product is greatly reduced. Which of the statements are true of the compound?
Chemistry
1 answer:
ad-work [718]3 years ago
6 0

Answer:

Adding more substrate would overcome  the effect of the compound

Explanation:

  • Enzymes are biochemical catalysts that speed up chemical reactions. They act on specific substrate to convert them to products.
  • Compounds known as inhibitors slow down the rate of enzyme activity.
  • Inhibitors are classified as competitive and non-competitive inhibitors.
  • Competitive inhibitors will compete with the substrate to bind the active sites on the enzyme. The effect of competitive inhibitors may be reduced by increasing the concentration of the substrate.
  • The compound added by the biologist was a competitive inhibitor and therefore adding more substrate would overcome its effect on enzyme catalysis
  • Non-competitive inhibitors binds the active site of the enzyme permanently and prevents the substrate from accessing the active sites.

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When 38.1 grams of a certain metal at a temperature of 90.0°C is added to 100.0mL of water at a temperature of 17.6°C in a perfe
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Answer:

a. qm = 627.3 J

b. qw = 627.3 J

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Explanation:

a.

Since, the calorimeter is completely insulated. Therefore,

Heat Lost by Metal = Heat Gained by water

qm = qw

qm = m₁C₁ΔT₁

where,

qm = heat lost by metal = ?

m₁ = mass of water = (density)(volume) = (1000 kg/m³)(100 mL)(10⁻⁶ m³/1 mL)

m₁ = 0.1 kg

C₁ = specific heat capacity of water = 4182 J/kg.°C

ΔT₁ = Change in Temperature of Water = 19.1°C - 17.6°C = 1.5°C

Therefore,

qm = (0.1 kg)(4182 J/kg.°C)(1.5°C)

<u>qm = 627.3 J</u>

<u></u>

b.

Since,

qm = qw

<u>qw = 627.3 J</u>

<u></u>

c.

qm = m₂C₂ΔT₂

where,

m₂ = mass of metal = 38.1 g = 0.0381 kg

C₂ = specific heat capacity of metal = ?

ΔT₂ = Change in Temperature of metal = 90°C - 17.6°C = 72.4°C

Therefore,

627.3 J = (0.0381 kg)(C₂)(72.4°C)

(627.3 J)/(0.0381 kg)(72.4°C) = C₂

<u>C₂ = 227.4 J/kg.°C</u>

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