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SIZIF [17.4K]
4 years ago
7

PLEASE HELP!!!!!How does boron differ from NEON

Chemistry
1 answer:
Simora [160]4 years ago
5 0
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What does Fe(NO3)2 + Cu stands for?​
Gwar [14]
Copper nitrate

Copper nitrate is the oxidizing agent as it gets reduced from +2 to 0 oxidization State and oxidize Fe from 0 to +2 state.
7 0
2 years ago
What are the differences between amorphous and crystalline solids? Give an example of each.
Eddi Din [679]

Answer: orderly arrangement of particles

Explanation:

In a crystaline solid, the particles that compose the solid are arranged or packed in an orderly manner to form a three dimensional crystal lattice with a defined structure. Sodium chloride is a crystaline solid.

In an amorphous solid, the particles that compose the solid aren't arranged in an orderly manner hence the solid tends to be brittle, e.g glass

7 0
4 years ago
Give the following for SO2 and BrF5:
frosja888 [35]

Answer:

The given molecules are SO2 and BrF5.

Explanation:

Consider the molecule SO2:

The central atom is S.

The number of domains on S in this molecule is three.

Domain geometry is trigonal planar.

But there is a lone pair on the central atom.

So, according to VSEPR theory,

the molecular geometry becomes bent or V-shape.

Hybridization on the central atom is

sp^{2}.

Consider the molecule BrF5:

The central atom is Br.

The number of domains on the central atom is six.

Domain geometry is octahedral.

But the central atom has a lone pair of electrons.

So, the molecular geometry becomes square pyramidal.

The hybridization of the central atom is sp^{3} d^{2}.

The shapes of SO2 and BrF5 are shown below:

6 0
3 years ago
What mass of carbon dioxide is produced upon the complete combustion of 26.5 L of propane (the approximate contents of one 5-gal
svet-max [94.6K]

Answer:

mCO2= 49.6932 kgCO2

Explanation:

Hello! Let's solve this!

First we propose the balanced equation C3H8 + 5O2 ---> 3CO2 + 4H2O

We see that each mole of C3H8 (propane) we get 3 moles of CO2

From the propane volume we can obtain the grams of propane used.

molpropane = 26.5L * (1000mL / 1L) * (0.621g / 1mL) * (1mol / 44g) = 374.01mol propane

mCO2 = 374.01molC3H8 * (3molCO2 / 1molC3H8) * (44gCO2 / 1molCO2) = 49369.32g * (1kg / 1000g) = 49.6932 kgCO2

mCO2= 49.6932 kgCO2

6 0
3 years ago
Which statement about the scientific veiws is correct?
hammer [34]
I think the answer will be b cuh
4 0
4 years ago
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