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2 years ago

Which of the following liquids would turn

Chemistry

1 answer:

adelina 88 [10]2 years ago

6 0

Answer:

orange juice because it a type of acid.

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13. A gas occupies 4.31 liters at a pressure of 0.755 atm. Determine the volume if the

wariber [46]

Answer:

13. 2.60 L.

14. 2.40 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and T are constant, and have different values of P and V:

(P₁V₁) = (P₂V₂)

13. A gas occupies 4.31 liters at a pressure of 0.755 atm. Determine the volume if the pressure is increased to 1.25 atm.

P₁ = 0.755 atm, V₁ = 4.31 L.

P₂= 1.25 atm, V₂ = ??? L.

∴ V₂ = (P₁V₁)/(P₂) = (0.755 atm)(4.31 L)/(1.25 atm) = 2.60 L.

14. 600.0 mL of a gas is at a pressure of 8.00 atm. What is the volume of the gas at 2.00 at m.

P₁ = 8.0 atm, V₁ = 600.0 mL.

P₂= 2.0 atm, V₂ = ??? L.

∴ V₂ = (P₁V₁)/(P₂) = (8.0 atm)(600.0 mL)/(2.0 atm) = 2400/0 mL = 2.40 L.

3 0

3 years ago

What color would litmus paper turn in a solution of baking soda? Explain your answer in terms of pH.

madam [21]

Blue

When red litmus paper comes into contact with any alkaline substance, it turns blue. Some examples of alkaline substances are ammonia gas, milk of magnesia, baking soda and limewater.

3 0

3 years ago

Alex17521 [72]

Answer: Iron

Explanation: There are little minnerals that make it magnetic.

5 0

2 years ago

At 1000 K, Kp=19.9 for the reaction Fe2O3(s)+3CO(g)<--->2Fe(s)+3CO2(g) What are the equilibrium partial pressures of CO an

SOVA2 [1]

Answer: The equilibrium concentration of CO is 0.243 atm

Explanation:

We are given:

Initial partial pressure of carbon dioxide = 0.902 atm

As, carbon dioxide is present initially. This means that the reaction is proceeding backwards.

For the given chemical equation:

$Fe_2O_3(s)+3CO(g)\rightleftharpoons 2Fe(s)+3CO_2(g)$

Initial: 0.902

At eqllm: 3x (0.902-3x)

The expression of $K_p$ for above equation follows:

$K_p=\frac{(p_{CO_2})^3}{(p_{CO})^3}$

We are given:

$K_p=19.9$

Putting values in above equation, we get:

$19.9=\frac{(0.902-3x)^3}{(3x)^3}\\\\x=0.0810$

So, equilibrium concentration of CO = 3x = (3 × 0.0810) = 0.243atm[/tex]

Hence, the equilibrium concentration of CO is 0.243 atm

6 0

3 years ago

Read 2 more answers

How does the solubility of a gas change with decreasing temperature?

dem82 [27]

It increases..........

4 0

3 years ago

Read 2 more answers