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2 years ago

Explain why the catalyst is used as a very fine powder and larger pieces of iron are not used.

Chemistry

1 answer:

Allushta [10]2 years ago

7 0

Answer:

<h2><u>Reason:</u></h2>

Catalyst is used as a very fine powder and larger pieces of iron are not used. This is because the surface area of catalyst needs to be large so that more of the surface is exposed to the substrate and more of the substrate is catalyzed.

<h2><u>Important Info:</u></h2>

=> Larger Pieces of Iron has a smaller surface area than the fine particles.

=> Larger the surface area of catalysts/enzymes , more will be the reaction rate and vice versa.

Hope this helped!

<h2>~AnonymousHelper1807</h2>

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The compound known as butylated hydroxytoluene, abbreviated as BHT, contains carbon, hydrogen, and oxygen. A 3.001 g sample of B

loris [4]

I believe here is the right question, so will just ignore the rest of the junk information from the previous message

The compound known as butylated hydroxytoluene, abbreviated as BHT, contains carbon, hydrogen, and oxygen. A 3.001 g sample of BHT was combusted in an oxygen rich environment to produce 8.990 g of CO2(g) and 2.944 g of H2O(g). Insert subscripts below to appropriately display the empirical formula of BHT

Answer:

$C_{15}H_{24}0$

Explanation:

A 3.001 g sample of BHT was combusted in an oxygen rich environment to produce 8.990 g of CO2(g) and 2.994 g of H2O(g).

If all the carbon in BHT is present in $CO_2$ and also, all the hydrogen in BHT is present in $H_2O$ , Then we can determine for the corresponding numbers of moles of Carbon(C) and Hydrogen (H) respectively as:

moles of $CO_2$ = $8.990 g*(\frac{1mole}{44.01g})$

= 0.2043 moles

∴ moles of C = 0.2043 moles

moles of $H_2O$ = $2.944 g *(\frac{1mole}{18.01g} )$

= 0.1635 moles

∴ moles of H = 2 × 0.1635 moles

= 0.327 moles

Since number of moles= $\frac{mass}{molarmass}$

number of moles of H = 0.327 moles

molar mass of H = 1.008 g/mol

∴ mass of H in the sample = 0.327 moles × 1.008 g/mol

= 0.329616g

mass of C in the sample can be calculated as = 0.2043 moles × $(\frac{12.01g}{1 mole} )$

= 2.453643 g

mass of C+H in the sample = 2.453643g + 0.329616g

= 2.783259 g

mass of O can be calculated as = 3.001 g - 2.783259 g

= 0.217741 g

∴ moles of O = 0.217741g × $(\frac{1mole}{16.0g})$

= 0.0136 moles

Now, since; we've gotten our data, we can now proceed to calculate for the empirical formula.

C H O

0.2043 0.327 0.0136

Dividing by the least number (0.0136) , we have :

$\frac{0.2043}{0.0136}$ $\frac{0.327}{0.0136}$ $\frac{0.0136}{0.0136}$

15.02 24.04 1

≅

15 24 1

Therefore, the empirical formula would be : $C_{15}H_{24}0$

7 0

2 years ago

In the compound potassium nitrate (KNO3), the atoms within the nitrate ion are held together with bonding, and the potassium ion

sveta [45]

In the compound potassium nitrate (KNO3), the atoms within the nitrate ion are held together with COVALENT bonding, and the potassium ion and nitrate ion are held together by IONIC bonding.

A covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs. Covalent bond is formed between two non-metals.

Ionic bonds form when one atom gives up one or more electrons to another atom. It is the complete transfer of valence electron(s) between oppositely charged atoms. Ionic bond is formed between metal (electropositive element) and non-metal(electronegative element)

In nitrate ions the Nitrogen (N) and Oxygen (O) both are non-metals and it involves the sharing of electron pairs between N and O atoms, so the bonding in Nitrate ( $NO_{3}^{-}$ ) ion is covalent bonding.

In potassium nitrate , Potassium (K) is a metal and Nitrate ( $NO_{3}^{-}$ ) ion is non-metal and it involves the complete transfer of valence electron between oppositely charged atoms (K+) and ( $NO_{3}^{-}$ ). So the bonding between Potassium and Nitrate is Ionic bonding.

NOTE : Bonding between Non-metals is Covalent bonding.

Bonding between Metal and Non-metals is Ionic bonding.

7 0

3 years ago

Roland is measuring a physical property of an object. He records the measurement:

Vsevolod [243]

Answer:

The correct answer is density. See the explanation below, please.

Explanation:

Roland measured density, which is a property that relates mass to volume, having units for example: grams / cm3

3 0

2 years ago

The pathway by which carbon is transferred from living organisms to the atmosphere is called:

Phoenix [80]

Answer:

cellular respiration

Explanation:

All exergonic processes produced in the cell, through which substances oxidize and chemical energy is released, are grouped under the name of cellular respiration, but to break down an organic molecule the cells employ, mainly dehydrogenations that can be carried carried out in the presence or absence of atmospheric O2 oxygen. There are therefore two types of breathing: aerobic respiration and anaerobic respiration. The latter also called fermentation.

Aerobic respiration (oxidative phosphorylation)

- Use molecular O2.

- It degrades glucose to CO2 and H2O

- Exergonic

- Recovers about 50% of chemical energy

- Present in most organisms.

- It uses enzymes located in the mitochondria.

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2 years ago

1. How many ATOMS of carbon are present in 7.48 grams of carbon monoxide ?

Salsk061 [2.6K]

Answer:

The answer is 1.61 × 10²³ atoms

Explanation:

To determine number of atoms, we will use the formula below

Number of atoms = number of moles (n) × avogadro's constant (6.02 x 10²³)

n was not provided, hence we will solve for n

n = mass/ molar mass

molar mass of carbon monoxide, CO (where C is 12 and O is 16) is 12 + 16 = 28

mass was provided in the question as 7.48

n = 7.48/28

n = 0.267

Hence,

number of atoms = 0.267 × 6.02 x 10²³

= 1.61 × 10²³ atoms

3 0

2 years ago