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BARSIC [14]
2 years ago
15

Which is NOT a component of galaxies? * F. Universe G. Stars H. Dust J. Planets​

Chemistry
1 answer:
Afina-wow [57]2 years ago
4 0

Answer:

F. Universe

Explanation:

Universe and Galaxies are two different things.

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Which choice is an example of a consumer? Question 9 options: tree fungi bee sun
xz_007 [3.2K]
The correct answer is C) Bee, any living thing, such as a bee, cannot make its own food therefor it is a consumer
3 0
2 years ago
Read 2 more answers
if the density of copper is 8.9g/cm^3 and the Volume of the sample is 23.4 mL what would be the mass? ​
Black_prince [1.1K]

Answer:

The mass of copper = 208.26 grams.

Explanation:

Density = mass / volume

8.9 = mass / 23.4

mass = 8.9 * 23.4

= 208.26 grams.

8 0
2 years ago
A 29.7 g sample of iron ore is treated as follows. The iron in the sample is all converted by a series of chemical reactions to
Softa [21]

<u>Answer:</u> The mass of iron in the ore is 10.9 g

<u>Explanation:</u>

We are given:

Mass of iron (III) oxide = 15.6 g

We know that:

Molar mass of Iron (III) oxide = 159.69 g/mol

Molar mass of iron atom = 55.85 g/mol

As, all the iron in the ore is converted to iron (III) oxide. So, the mass of iron in iron (III) oxide will be equal to the mass of iron present in the ore.

To calculate the mass of iron in given mass of iron (III) oxide, we apply unitary method:

In 159.69 g of iron (III) oxide, mass of iron present is (2\times 55.85)=111.7g

So, in 15.6 g of iron (III) oxide, mass of iron present will be = \frac{111.7g}{159.69g}\times 15.6g=10.9g

Hence, the mass of iron in the ore is 10.9 g

7 0
3 years ago
Suppose that you add 28.8 g of an unknown molecular compound to 0.250 kg of benzene, which has a K f Kf of 5.12 oC/m. With the a
Brrunno [24]

Answer:

THE MOLAR MASS OF THE UNKNOWN COMPOUND IS 242.02 g/mol.

Explanation:

First:

Calculate the change in freezing point:

          Freezing point of pure benzene = 5.5°C

Change in temperature = 5.5 - 3.06 = 2.44 °C

Second:

Using the formula:

Δt = i Kf m

Let's assume i = 1

Kf = 5.12 °C/m

M = x / 0.250 kg of benzene

Then we can calculate x which is the molarity

Re-arranging the formula, we have:

m = Δt / i Kf

x / 0.250 = 2.44 / 1 * 5.12

x = 2.44 * 0.250 / 5.12

x = 0.61 / 5.12

x = 0.119 M

Since it is well known that molarity is the mass of a substance divided by its molar mass. We can then calculate the molar mass.

Molar mass = Mass / molarity

Molar mass = 28.8 g / 0.119 M

Molar mass =242.02 g/mol

Hence, the molar mass of the unknown molecular compound is 242.02 g/mol.

4 0
3 years ago
Which set of numbers gives the correct possible values of l for n = 3?
Free_Kalibri [48]
0 1 2 3
0 and 3 is 3
1 and 2 is 3
3 0
3 years ago
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