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djverab [1.8K]
3 years ago
8

Domestic bees make their honeycomb by starting with a single hexagonal cell, then forming ring after ring of hexagonal cells aro

und the initial cell, as shown. The number of cells in successive rings forms an arithmetic sequence..
A-Write a rule for the number of cells in the
ring.


b. How many cells are in the honeycomb after the ninth ring is formed?

Mathematics
1 answer:
maw [93]3 years ago
7 0

Answer:

aₙ= 6 n

Step-by-step explanation:

A honey comb cell contain 6 cells

a₁ = 6

d=6

aₙ = 6 + (n-1)6

   = 6 n

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Please help please giving out brainless
Readme [11.4K]

Answer:

C

Step-by-step explanation:

The length of arc AC (L) is calculated as

L = circumference of circle × fraction of circle

  = 2πr × \frac{150}{360}

  = 2π × 12 × \frac{5}{12}

 = 2π × 5

 = 10π ≈ 31.42 → C

4 0
2 years ago
Which choices are equivalent to the exponential expression below? check all that apply. (2/3)^3
rosijanka [135]

Answer:

B. (2/3) x (2/3) x (2/3)

C. 8/27

D. 2^3 /3^3

Step-by-step explanation:

You need to know the following property

\LARGE \left(\frac{a}{b} \right)^c = \frac{a^c}{b^c}

Exponent also means you're multiplying the same number for an 'n' number of times.

For example, 2^3 = 2 * 2 * 2

we multiply it by itself 3 times since 3 is the exponent.

x^y

x is the base, y is the exponent

we read it as x to the power of y

If the exponent is 2, we say it as x squared

If the exponent is 3, we say it as x cubed

4 0
3 years ago
Can anyone explain to me how to do this question ? ty !!​
julia-pushkina [17]

Step-by-step explanation:

use a little imagination.

the whole thing is a combination of churches and half- circles.

and you know the formula for the area of a circle ?

A = pi×r²

so, the only difficulty is to find the circles and then the radius of each involved circle.

when you look at the picture, the shaded area is almost identical to the lower half of the main circle.

2 bumps "look" over into the other side, but one equally sized bump is removed from this lower half.

so, as a first step we will calculate the area of the lower half of the main circle.

the diameter is 24 m, so the radius is half of that : 12m

the area of the large circle is therefore

pi×12² = 144×pi m²

since we only need the (lower) half, we divide this by 2 :

144×pi / 2 = 72×pi m²

the bumps up and down are actually half-circles too. just of smaller circles.

since AB = BC = CD, we know each of these lines are 1/3 of the main diameter AD.

so, the diameter of the smaller circles is 24/3 = 8 m

and their radius is half of that = 8/2 = 4m

the area of such a small circle is therefore

As = pi×4² = 16×pi m²

and a small half-circle area is then

16×pi / 2 = 8×pi m²

so, for the full shaded area I need to take the large half-circle and add 2 small half-circles, and then subtract 1 small half-circle.

so, in total I only need to add 1 small half-circle.

Ashaded = 72×pi + 8×pi = 80×pi m²

5 0
2 years ago
What is the correct answer to this?
mel-nik [20]

Answer:

1,436.03

Step-by-step explanation:

V=4/3*pi*r^3

V=4/3*3.14*7^3

V=1,436.03

7 0
2 years ago
Can someone pls help me with this answer?
Kruka [31]
As a mixed number it’s 7 6/9 -not too sure about improper fraction. just know that repeating decimals always have a 9 as the denominator -hope that helps :)
8 0
2 years ago
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