Answer:
![20](https://tex.z-dn.net/?f=20)
Step-by-step explanation:
GIVEN: Tina, Sijil, Kia, vinayash Alisha and shifa are playing game by forming two teams Three players in each team.
TO FIND: how many different ways can they be put into two teams of three players.
SOLUTION:
Total number of players ![=6](https://tex.z-dn.net/?f=%3D6)
total teams to be formed ![=2](https://tex.z-dn.net/?f=%3D2)
total players in one team ![=3](https://tex.z-dn.net/?f=%3D3)
we have to number of ways of selecting
players for one team, rest
will go in other team.
Total number of ways of selecting
players ![=^6C_3](https://tex.z-dn.net/?f=%3D%5E6C_3)
![=\frac{6!}{3!3!}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B6%21%7D%7B3%213%21%7D)
![=20](https://tex.z-dn.net/?f=%3D20)
Hence total number of different ways in which they can be put into two different teams is
-np-4≤2(c-3)
-np-4≤2x-6
-np≤2x-2
-n≤(2x-2)/p
n≥-((2x-2)/p)
Answer:
12
trust me it works i just took the test.
Mean: add all the numbers, then dived the sum by hwo many numbers there are.
72.3 + 74.5 + 81.1 + 72.3 + 75.6 + 79 = 754.8
754.8 ÷ 6 = 75.8
Mean = 75.8°
Median: Put all the number in order from lowest to highest. The middle number is the median. If there are two numbers in the middle, add them then divide the sum by 2.
72.3, 72.3, 74.5, 75.6, 79, 81.1
74.5 + 75.6 = 150.1
150.1 ÷ 2 = 75.05 ~ 75
Median = 75°
Step-by-step explanation:
as the other guy say it a for real