Answer:
Option E is correct. none of the above is correct
Explanation:
Step 1: Data given
Solid Iron (III) = Fe^3+
iron (III) oxide = Fe2O3
Molar mass Fe = 55.845 g/mol
Molar mass Fe2O3 = 159.69 g/mol
Step 2: The balanced equation:
4Fe + 3O2 → 2Fe2O3
4 moles of iron will need 2 moles of oxygen gas to fully react
⇒ This is false 4 moles of iron will need 3 moles of oxygen gas to fully react
B.12 moles of iron, if reacted completely, can produce 8 moles of iron (III) oxide.
⇒ This is false: When 12 moles of iron completely react, we can produce 12/2 = 6 moles of Fe2O3
C.9 moles of oxygen can produce 9 moles of Iron (III) oxide
⇒ This is false; 9 moles of O2 can produce 6 moles of Fe2O3
D.6 moles of oxygen can react completely to produce 6 moles of iron (III) oxide.
⇒ This is false 6 moles of O2 will react completely to produce 4 moles of Fe2O3
E.none of the above
Answer:
The temperature is 419,1 K
Explanation:
We use the formula PV=nRT T=PV/nR
T=1,5 atm x 12,6 L/0,55 mol x 0,082 l atm/K mol
T= 419,0687361 K
Answer:
The pressure, when the volume is reduced to 7.88L, is 846 torr (option A)
Explanation:
Step 1: Data given
The temperature of a gas = 25.0°C
AT 25 °C the gas occupies a volume of 10.0L and a pressure of 667 torr.
The volume reduces to 7.88 L but the temperature stays constant.
Step 2: Boyle's law
(P1*V1)/T1 = (P2*V2)/T2
⇒ Since the temperature stays constant, we can simplify to:
P1*V1 = P2*V2
⇒ with P1 = the initial pressure 667 torr
⇒ with V1 = the initial volume = 10.0 L
⇒ with P2 = the final pressure = TO BE DETERMINED
⇒ with V2 = the final volume = 7.88L
P2 = (P1*V1)/V2
P2 = (667*10.0)/7.88
P2 = 846 torr
The pressure, when the volume is reduced to 7.88L, is 846 torr (option A)
Answer: It depends on the type of chemical reaction that formed the compound.
Explanation:
Exothermic reactions give off the heat to the reaction environment, so the compound feels hotter.
Endothermic reactions absorb the heat from the reaction environment and the compound feels cooler.
