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svp [43]
3 years ago
9

ROY G BIV arranges the colors of the rainbow *

Chemistry
1 answer:
Elanso [62]3 years ago
8 0

Answer:

Wavelengths..

Explanation:

The colors we see always go from red, which is least refracted, through orange, yellow, green, blue, indigo and violet -- Roy G Biv. The blue, indigo and violet wavelengths are refracted the most as sunlight passes through raindrops.

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Consider the reaction CaCN2 + 3 H2O → CaCO3 + 2 NH3 . This reaction has a 75.6% yield. How many moles of CaCN2 are needed to obt
kherson [118]

Answer: Thus 0.724 mol of CaCN_2 are needed to obtain 18.6 g of NH_3

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} NH_3=\frac{18.6g}{17g/mol}=1.09moles

CaCN_2+3H_2O\rightarrow CaCO_3+2NH_3

According to stoichiometry :

2 moles of NH_3 are produced by = 1 mole of CaCN_2

Thus 1.09 moles of NH_3 will be produced by =\frac{1}{2}\times 1.09=0.545moles  of CaCN_2

But as yield of reaction is 75.6 %, the amount of CaCN_2 needed is =\frac{0.545}{75.6}\times 100=0.724

Thus 0.724 mol of CaCN_2 are needed to obtain 18.6 g of NH_3

3 0
3 years ago
What is a chemical off of the periodic table that is sticky
Alex73 [517]
I think it’s the one that has a Br
3 0
3 years ago
Read 2 more answers
A 45 mL sample of nitrogen gas is cooled from 135ºC to 15C in a container that can contract or expand at constant pressure. Wha
Vanyuwa [196]

Answer:

V₂ =31.8 mL

Explanation:

Given data:

Initial  volume of gas = 45 mL

Initial temperature = 135°C (135+273 =408 K)

Final temperature = 15°C (15+273 =288 K)

Final volume of gas = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 45 mL × 288 K / 408 k

V₂ = 12960 mL.K / 408 K

V₂ =31.8 mL

8 0
3 years ago
A solution of malonic acid, H2C3H2O4 , was standardized by titration with 0.1000 M NaOH solution. If 21.17 mL of the NaOH soluti
MrRa [10]

Answer: The molarity of the malonic acid solution is 0.08335 M

Explanation:

H_2C_3H_2O_4 +2NaOH\rightarrow Na_2C_3H_2O_4+2H_2O

To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2C_3H_2O_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=12.70mL\\n_2=1\\M_2=0.1000M\\V_2=21.17mL

Putting values in above equation, we get:

2\times M_1\times 12.70=1\times 0.1000\times 21.17\\\\M_1=0.08335M

Thus the molarity of the malonic acid solution is 0.08335 M

5 0
3 years ago
WILL GIVE BRAINLIEST
Sav [38]

Answer:

the answer is A

Explanation:

5 0
3 years ago
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