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svp [43]
3 years ago
9

ROY G BIV arranges the colors of the rainbow *

Chemistry
1 answer:
Elanso [62]3 years ago
8 0

Answer:

Wavelengths..

Explanation:

The colors we see always go from red, which is least refracted, through orange, yellow, green, blue, indigo and violet -- Roy G Biv. The blue, indigo and violet wavelengths are refracted the most as sunlight passes through raindrops.

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How many grams of O2 are needed to react with 8.15 g of C2H2?
xxTIMURxx [149]

Answer:

25.08 grams of O₂ are needed to react with 8.15 g of C₂H₂.

Explanation:

The balanced reaction is:

2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O

By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:

  • C₂H₂: 2 moles
  • O₂: 5 moles
  • CO₂: 4 moles
  • H₂O: 2 moles

The molar mass of each compound is:

  • C₂H₂: 26 g/mole
  • O₂: 32 g/mole
  • CO₂: 44 g/mole
  • H₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • C₂H₂: 2 moles* 26 g/mole= 52 g
  • O₂: 5 moles* 32 g/mole= 160 g
  • CO₂: 4 moles* 44 g/mole= 176 g
  • H₂O: 2 moles* 18 g/mole= 36 g

Then you can apply the following rule of three: if by stoichiometry 52 grams of C₂H₂ react with 160 grams of O₂, 8.15 grams of C₂H₂ react with how much mass of O₂?

mass of O_{2} =\frac{8.15 grams of C_{2} H_{2}*160 grams of O_{2}  }{52 grams of C_{2} H_{2}}

mass of O₂= 25.08 grams

<u><em>25.08 grams of O₂ are needed to react with 8.15 g of C₂H₂.</em></u>

8 0
3 years ago
I have a few minutes left! Will award 25 points!!
Serggg [28]
A sizing beads it help counter balance
3 0
4 years ago
P is the dominant allele for purple. p is the recessive allele for white. A Pp flower crosses with a pp flower. What are the pos
malfutka [58]

Answer:

Pp, Pp, pp, pp, 50% chance at purple and 50% chance at white

Explanation:

5 0
3 years ago
An aqueous solution is prepared by dissolving 15.6 g of Cu(NO3)2 ⋅ 6 H2O in water and diluting to 345 mL of solution. What is th
Vladimir [108]

<u>Answer:</u> The molarity of NO_3^- ions in the solution is 0.306 M

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of solute (Cu(NO_3)_2.6H_2O) = 15.6 g

Molar mass of (Cu(NO_3)_2.6H_2O) = 295.6 g/mol

Volume of solution = 345 mL

Putting values in above equation, we get:

\text{Molarity of }Cu(NO_3)_2.6H_2O=\frac{15.6g\times 1000}{295.6g/mol\times 345mL}\\\\\text{Molarity of }Cu(NO_3)_.6H_2O=0.153M

As, 1 mole of (Cu(NO_3)_2.6H_2O) produces 1 mole of copper (II) ions and 2 moles of nitrate ions.

So, molarity of NO_3^- ions = (2 × 0.153) = 0.306 M

Hence, the molarity of NO_3^- ions in the solution is 0.306 M

3 0
3 years ago
Which of the following properties can be
Aleonysh [2.5K]

Answer:

Ability to conduct electricity

Melting point

4 0
3 years ago
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