All categories

3 years ago

Which of the following is an example of consideration?

Chemistry

1 answer:

Hunter-Best [27]3 years ago

5 0

Answer:

B. Opening a door for someone who is carrying things

You might be interested in

When collecting your solid, why should the filter paper in the Buchner funnel be wetted with some of the cold recrystallization

Mnenie [13.5K]

Answer: It is important to wet the filter paper in the Buchner funnel first with cold re crystallization solvent before the re crystallization mixture being filtered to minimize gaps around the edges of the filter paper which can prevent mechanical impurities from passing through. This gives better filtration where most impurities can be filtered. Furthermore, it provides good vacuum.

6 0

3 years ago

Jerod used a golf club to hit a ball what was the action and reaction

Triss [41]

The action was him hitting the ball the reaction was the ball moving after being hit

6 0

3 years ago

Read 2 more answers

Choose the atom or ion that is larger. Select one: a. Br-1 b. Br

solniwko [45]

Answer:

Br^-1

Explanation:

It is an ion that gained an extra electron making it 36 electrons but the other. one is in the neutral state with 35 electrons

7 0

2 years ago

Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el

givi [52]

Answer: The amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

Explanation:

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of particles.

We know that:

Charge on 1 electron = $1.6\times 10^{-19}C$

Charge on 1 mole of electrons = $1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C$

$Cu^{2+}+2e^-\rightarrow Cu$

$2\times 96500=193000C$ is passed to deposit = 1 mole of copper

63.5 g of copper is deposited by = 193000 C

$14\times 1000g=14000g$ of copper is deposited by = $\frac{193000}{63.5}\times 14000=42551181 C$

To calculate the time required, we use the equation:

$I=\frac{q}{t}$

where,

I = current passed = 40.0 A

q = total charge = 42551181 C

t = time required = ?

Putting values in above equation, we get:

$40.0=\frac{42551181 C}{t}\\\\t=1063779sec$

Converting this into hours, we use the conversion factor:

1 hr = 3600 seconds

So, $1063779s\times \frac{1hr}{3600s}=295hr$

Hence, the amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

3 0

3 years ago

How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 53.2 grams of hydrogen gas in the

olchik [2.2K]

The balanced chemical reaction is:

2Na + 2H2O → 2NaOH + H2

We first use the amount of hydrogen gas to be produced and the molar mass of the hydrogen gas to determine the amount in moles to be produced. Then, we use the relation from the reaction to relate H2 to Na.

53.2 g H2 ( 1 mol / 2.02 g ) ( 2 mol Na / 1 mol H2 ) ( 22.99 g / 1 mol ) = 1210.96 g Na

1210.96 g Na ( 1 mL / 0.97 g ) = 1248.41 mL Na needed

7 0

3 years ago