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olga2289 [7]
3 years ago
7

Somebody help me asap please giving brainliest

Chemistry
1 answer:
Serggg [28]3 years ago
3 0

Answer:

fire > rocks > air

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Bf3 can be octet or not​
makvit [3.9K]

Answer:

(BH3 follows the octet rule by dimerizing, as Hadi Kurniawan AR pointed out.) For H and He, an "octet" = 2 electrons. Boron does prefer to follow the octet rule, in that it likes to form borate compounds such as NaBH4. It also is happy to form compounds with elements with lone pairs.

7 0
2 years ago
Zn + 2HCl ---> ZnCl2 + H2 1. Is the equation above balanced or unbalanced? How do you know? (Hint: How many atoms of each typ
Arisa [49]

Answer:Balance. Acid+metal->salt+hydrogen.1 molecule od zinc contains 1 zinc atom.2 molecule of HCl contains 2 atoms hydrogen and 2 chlorine.1 molecule of Zncl2 contain one atom of zinc and two atom of chlorine.And two 2 atoms of hydrogen.

Explanation:

5 0
2 years ago
When a rock falls from outer space all the way to the groung, its called a?
goblinko [34]
It's called a meteorite.
6 0
2 years ago
A sample of CO2 weighing 86.34g contains how many molecules?
irakobra [83]

Answer:

1.181 × 10²⁴ molecules CO₂

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

86.34 g CO₂

<u>Step 2: Identify Conversion</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

<u />86.34 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} ) = 1.18141 × 10²⁴ molecules CO₂

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

1.18141 × 10²⁴ molecules CO₂ ≈ 1.181 × 10²⁴ molecules CO₂

4 0
3 years ago
Writing the net ionic equation
vazorg [7]

First write the molecular equation with states:


(NH4)2S (aq) + 2AgNO3(aq) → Ag2S (s) + 2NH4NO3


Now write a full ionic equation by separating into ions all substances that dissociate: anything (s) (g) or (l) does not dissociate


2NH4 + (aq) + S 2-(aq) + 2Ag+ (aq) + 2NO3- (aq) → Ag2S(s) + 2NH4 + (aq) + 2NO3- (aq)


To write the NET IONIC equation, inspect the full ionic equation above and delete anything that appears on both sides of the → sign:


Net ionic equation:

S 2-(aq) + 2Ag + (aq) → Ag2S(s)

3 0
2 years ago
Read 2 more answers
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