Answer:
CH₃CH₂CH₂COOH.
Explanation:
To know which option is correct, let us hydrolysed the given ester. This is illustrated in the attached photo.
Hydrolysis of ester involves breaking the ester bond by a water molecule to produce the corresponding alcohol and carboxylic acid.
From the reaction given in the attached photo, we can see that the carboxylic acid needed to produce the desired ester is butanoic acid, CH₃CH₂CH₂COOH.
The radiosity of this surface is 299.95W/m².
<h3>
Calculation :</h3>
Given, € 0.8
Ta=0°C 273K
For opaque body., T = 0
a+ p = 1
€ = a (Kirchoff's Law)
p = (1-E)
Radiosity = leaving energy from the surface
= px 240 +€σT4
= (1-E) × 240 +0.8 x 5.67 x 10-8 (2734)
= (1-0.8) × 240 +0.8 x 5.67 × 10-8 (2734)
= 299.95W/m²
So, now after doing the calculations we can say that the radiosity of the surface was 299.95W/m².
To know more about Radiosity please click here : brainly.com/question/14937321
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Answer:
34.8 moles of O
Explanation:
First we break down Al2(SO4)3 and look at SO4 only. In this compound, there are already 4 moles of O. Then you see that there are 3 moles of (SO4), meaning there are 3*4 moles of O = 12 moles in the entire compound. Then you look at the question, where it's asking for 2.9 moles of the entire Al2(SO4)3 compound, so you multiply 2.9*12 = 34.8 total moles of O.
Um definitely under .00001
Answer:
Yesssss i really don't wanna go back to school
