Answer:
Calcium salts give bone its a. tensile strength. b. torsional strength. c. flexibility. d. compressional strength.
The answer is Option D (Compressional strength)
Explanation:
Calcium is the most abundant mineral in the body, most of the calcium in the body are found in the bones and teeth. Calcium helps the body with not only building strong bones and teeth, but also assisting the body in sending and receiving nerve signals. If blood calcium gets too high or too low, the muscles and nerves will not function.
Bone which serves as a storage area for calcium are mostly made of the protein collagen, forms the skeletal framework of all vertebrates, and it plays a major role in calcium balance in the blood. Bone exhibits four types of cells: osteoblasts, bone lining cells, osteocytes, and osteoclasts. Functions of bone includes structural support of the body, protection of internal organs, attachment of the muscles, production of blood cells.
Calcium salts form crystals that give bones great strength. Bone mineral is formed from carbonated hydroxyapatite. Calcium hydroxyapatite is a naturally occurring mineral form of calcium apatite, it contains magnesium and carbonate and it is identical to the substance in teeth and bones. The collagen fibers give bone its tensile strength, and hydroxyapatite give bone its compressive strength.
Answer:
An insulated beaker with negligible mass contains liquid water with a mass of 0.205kg and a temperature of 79.9 °C How much ice at a temperature of −17.5 °C must be dropped into the water so that the final temperature of the system will be 31.0 °C? Take the specific heat for liquid water to be 4190J/Kg.K, the specific heat for ice to be 2100J/Kg.K, and the heat of fusion for water to be 334000J/kg.
The answer to the above question is
Therefore 0.1133 kg ice at a temperature of -17.5 ∘C must be dropped into the water so that the final temperature of the system will be 31.0 °C
Explanation:
To solve this we proceed by finding the heat reaquired to raise the temperature of the water to 31.0 C from 79.9 C then we use tht to calculate for the mass of ice as follows
ΔH = m×c×ΔT
= 0.205×4190×(79.9 -31.0) = 42002.655 J
Therefore fore the ice, we have
Total heat = mi×L + mi×ci×ΔTi = mi×334000 + mi × 2100 × (0 -−17.5) = 42002.655 J
370750×mi = 42002.655 J
or mi = 0.1133 kg
Therefore 0.1133 kg ice at a temperature of -17.5 ∘C must be dropped into the water so that the final temperature of the system will be 31.0 °C
Answer:
boiling point and melting point.
Answer:
i answered your other post with it
Explanation:
