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3 years ago

Which was a testable idea that J.J. Thomson developed through his experiments?

Chemistry

2 answers:

Elenna [48]3 years ago

7 0

<u>Answer:</u> The correct statement is atoms contain small, negatively charged particles.

<u>Explanation:</u>

J.J.Thomson was a scientist which discovered electrons that are present in an atom.

He did an experiment and gave a model for this. The experiment conducted by him was Cathode Ray experiment and the model given by him was Plum pudding model.

From cathode ray, he showed that the cathode ray was composed of a negatively charged particles and named it as electrons. From plum pudding experiment, he said that the electrons are embedded in the atom. These particles carry negative charge and are very small as compared to the atom.

Hence, the correct statement is atoms contain small, negatively charged particles.

LenaWriter [7]3 years ago

3 0

Atoms contains small, negatively charged particles. His experiment showed that an atom contains negatively charged particles which was later known as electrons. This was confirmed by the Cathode Ray Experiment he conducted.

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A 100. g iron rod is heated to an unknown initial temperature. While cooling down to a temperature of 25.0 degree C, the rod rel

AfilCa [17]

Answer: a) $38.3^0C$

Explanation:

As we know that,

$q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

where,

q = heat released = -600.2 J

$m$ = mass of iron rod =100 g

$T_{final}$ = final temperature = $25.^0C$

$T_{initial}$ = initial temperature = ?

$c$ = specific heat of iron = $0.452J/g^0C$

Now put all the given values in equation, we get

$-600.2J=100\times 0.452J/g^0C\times (25.0-T_{initial})^0C]$

$T_{initial}=38.3^0C$

Therefore, the initial temperature of iron rod was $38.3^0C$

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