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3 years ago

Which of the subshells in the electron configuration of hf behave as core orbitals?

1 answer:

3 0

<span>Of all the sub-shells shown ( 1s ,2s ,2p ,3s ,3p ,4s ,3d ,4p ,5s ,4d ,5p ,6s ,4f ,5d) the ones that act as core orbital of HF (Hydrogen Fluoride) is 6s and 5d</span>

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If a bullet travels at 407.0 m/s, what is its speed in miles per hour? Number click to edit mi/h For the same bullet travelling

kaheart [24]

Answer : The speed in miles per hour is 22 mile/hr.

The speed in yard per min is 26617.8 yard/min

Explanation :

The conversion used for meters to miles is:

$1m=100cm\times \frac{1in}{2.54cm}\times \frac{1ft}{12in}\times \frac{1mile}{5280ft}$

The conversion used for second to hour is:

$1s=\frac{1}{60}min\times \frac{1hr}{60min}$

The conversion used for meter per second to mile per hour is:

$1\frac{m}{s}=\frac{100cm\times \frac{1in}{2.54cm}\times \frac{1ft}{12in}\times \frac{1mile}{5280ft}}{\frac{1}{60}min\times \frac{1hr}{60min}}$

As we are given the speed of 407.0 meter per second. Now we have to determine the speed in miles per hour.

$1m/s=2.2mile/hr$

So, $407.0m/s=\frac{2.2mile/hr}{1m/s}\times 407.0m/s=895.4mile/hr$

Therefore, the speed in miles per hour is 22 mile/hr.

The conversion used for meter to yard

1m = 1.09 yard

The conversion used for second to hour is:

$1s=\frac{1}{60}min$

The conversion used for meter per second to mile per hour is:

$1m/s=\frac{1.09yard}{frac{1}{60min}}$

$1m/s=65.4yard/min$

As we are given the speed of 407.0 meter per second. Now we have to determine the speed in yards per min

$1m/s=65.4yard/min$

So, $407.0m/s=\frac{65.4yard/min}{1m/s}\times 407.0m/s=26617.8yard/min$

Therefore, the speed in yard per min is 26617.8 yard/min

7 0

2 years ago

Alecsey [184]

Answer:

<h3>no it is not allowed</h3>

Explanation:

<h3>Liwis structure shows the elements symbol with dots thet represents valance electrons ; in second row elements their atomic number is 3 up to 10 , from Li up to Ne from their electron configuration their valance electron will be from 1 up to 8 respectivelly ,if lewis structure represents the element with it is symbol and dots that represents valance electron the second row elements cannot have more than an octet of valance electrons surrounding it.</h3>

<h3>I think it is help ful for you </h3>

3 0

3 years ago

What determines the strength of the attraction between molecules?

alexandr402 [8]

To determine strength of attractive forces between the molecules the size of the molecules, their polarity (dipole moment), and their shape. ... If two molecules have about the same size and similar shape, the dipole-dipole intermolecular attractive force increases with increasing polarity.

5 0

3 years ago

Read 2 more answers

What specific electrophile does benzene attack when it undergoes nitration??

Deffense [45]

<span><span>The reaction is as follows:
C6H6 </span>+ HNO3 + H2SO4 ------------> </span>C6H5NO2<span> + H</span>2<span>O
(BENZENE) (NITRIC ACID)(CATALYST)
</span>NO2(+) is the electrophile that acctacks on the benzene ring in nitration process.

7 0

3 years ago

A 3.42 gram sample of an unknown gas is found to occupy a volume of 1.90 L at a pressure of 547 mm Hg and a temperature of 33 °C

liq [111]

Use the Ideal Gas Law to find the moles of gas first.

Be sure to convert T from Celsius to Kelvin by adding 273.

Also I prefer to deal with pressure in atm rather than mmHg, so divide the pressure by 760 to get it in atm.

PV = nRT —> n = PV/RT
P = 547 mmHg = 547/760 atm = 0.720 atm
V = 1.90 L
T = 33°C = 33 + 273 K = 306 K
R = 0.08206 L atm / mol K

n = (0.720 atm)(1.90 L) / (0.08206 L atm / mol K)(306 K) = 0.0545 mol of gas

Now divide grams by mol to get the molecular weight.

3.42 g / 0.0545 mol = 62.8 g/mol

3 0

3 years ago