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elena55 [62]
4 years ago
13

Which of the subshells in the electron configuration of hf behave as core orbitals?

Chemistry
1 answer:
Nesterboy [21]4 years ago
3 0
<span>Of all the sub-shells shown ( 1s ,2s ,2p ,3s ,3p ,4s ,3d ,4p ,5s ,4d ,5p ,6s ,4f ,5d) the ones that act as core orbital of HF (Hydrogen Fluoride) is 6s and 5d</span>
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What is orbital theory of bonding in metals
lianna [129]
Metals of Group 1 donate 1 electron from its ns orbital to form ionic bond, where n is the no. of its outermost shell. 
Metals of Group 2<span> donate 2 electrons from its ns orbital to form ionic bond, where n is the no. </span>of its <span>outermost shell. </span>
5 0
3 years ago
Which of the following is true of mixtures?
SCORPION-xisa [38]

A. a mixture is a combination of two or more substances in which each substance retains its own properties.

4 0
3 years ago
How many grams of hydrochloric acid are produced when 15.0 grams NaCl react with excess H2SO4 in the reaction
e-lub [12.9K]

Answer:

11.65 g

Explanation:

Amount of NaCl  = 15.0 grams

amount of H₂SO₄ = Excess

mass of hydrochloric acid (HCl) = ?

Solution:

To solve this problem first we will look for the reaction that NaCl react with  H₂SO₄

Reaction:

         2NaCl + H₂SO₄ --------> 2 HCl + Na₂SO₄

As the  H₂SO₄ is in excess so the amount of hydrochloric acid (HCl) depends on the amount of NaCl as it its act as limiting reactant.

Now if we look at the reaction

         2NaCl + H₂SO₄ --------> 2HCl + Na₂SO₄

           1 mol                              2 mol  

Now convert moles to mass

Then

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Molar mass of HCl = 1 + 35.5 = 36.5 g/mol

So,

            2NaCl           +      H₂SO₄     -------->       2HCl        +     Na₂SO₄

      2 mol (58.5 g/mol)                                    2 mol (36.5 g/mol)

              94 g                                                           73 g

So if we look at the reaction; 94 g of NaCl gives with 73 g of hydrochloric acid (HCl) in a this reaction, then how many grams of hydrochloric acid (HCl) will produce from 15.0 g of NaCl

For this apply unity formula

           94 g of NaCl  ≅ 73 g of HCl

           15.0 g of NaCl  ≅ X g of HCl

By Doing cross multiplication

           X g of HCl = 73 g x 15.0 g / 94 g

           X g of HCl = 11.65 g

11.65 g of hydrochloric acid (HCl) will produce by 15.0 g of NaCl

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3 years ago
Whatvdo you meant by acid and base​
larisa86 [58]

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3 0
3 years ago
Read 2 more answers
How many grams of H,O are needed to produce 13 g of NaOH? 2 Na,O2 + 2 H20-4 NaOH + O2
fgiga [73]

Answer:

This is a typical stoichiometry question.To answer this question you want to get a relationship between

N

a

2

O and NaOH.

So you can get a relationship between the moles of

N

a

2

O

and moles of NaOH by the concept of stoichiometry.

N

a

2

O +

H

2

O ----------------> 2 NaOH.

According to above balanced equation we can have the stoichiometry relationship between

N

a

2

O and NaOH. as 1:2

It means 1 moles of

N

a

2

O is required to react with one mol of

H

2

O to produce 2 moles of NaOH.

in terms of mass 1 mole of

N

a

2

O has mass 62 g on reaction with water produces 2 moles of NaOH or 80 g of NaOH.

62 g of

N

a

2

O produces 80 g of NaOH.

1g of NaOH is produced from 62/80 g of

N

a

2

O

1.6 x

10

2

g of NaOH will require 62 x 1.6 x

10

2

g / 80 of

N

a

2

O

124g of

N

a

2

O.

Explanation:

3 0
3 years ago
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