Answer:
1120 gm
Explanation:
6. Consider the reaction: CzHo (g) + 02 (8) - 4 CO2(g) + 6H2O (1)
(a) Balance the equation.
(b) How many grams of oxygen are required to react with 10 moles of ethane for a complete
combustion reaction?
FIRST, CORRECT THE EQUATION THEN BALANCE
2C2H6(G) + 7O2------------> 4CO2 + 6H2O
so for 10 moles of ethane, we need
7 X 5 = 35 MOLES O2
=35 MOLES O2
O2 HAS A MOLAR MASS OF 2X16 = 32 gm
35 MOLES OF O2 HAS A MASS OF 35 X 32 =1120 gm
Answer:
The answer to your question is: = 2.52 x 10²¹ molecules
Explanation:
mass of fuel = 13.56 - 13.53 = 0.04 g of fuel
mass of oxygen = ?
mass of water = 0.054 g
mass of carbon dioxide = 0.1198 g
To solve this problem just remember the Lavoisier law of conservation of mass that says: Mass is neither created nor destroyed in chemical reactions,
Reaction:
Fuel + Oxygen ⇒ Water + Carbon dioxide
0.04 + mass O2 ⇒ 0.054 + 0.1198
mass O2 = 0.054 + 0.1198 - 0.04
mass O2 = 0.1338 g
MW O2 = 32
1 mol of O2 -------------------- 32 g
x ------------------- 0.1338g
x = 0.1338(1) / 32 = 0.0042 moles
1 mol ----------------- 6,023 x 10 ²³ molecules
0.0042 moles ----- x
x = 0.0042 (6,023 x 10 ²³ ) / 1 = 2.52 x 10²¹ molecules
Eric Wu cannot take his pictures on any night because as the Moon orbits the sun different angles of the illuminated half of the Moon is being shown as the days go on. So on some nights the areas of the Moon that Eric Wu wants to take pictures of may not be shown on the Moon because the area is not facing earth.
Answer:
29.575%
Explanation:
Data provided:
Calories taken in daily diet = 2000
Recommended amount of fat = 65 grams
Average number of calories for fat = 9.1 calories / g
Thus,
Number of calories in the diet with average number of calories for fat
= Recommended amount of fat × Average number of calories for fat
= 65 × 9.1
= 591.5 calories
Therefore,
the percentage of calories in his diet supplied = ( 591.5 / 2000 ) × 100
= 29.575%