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jeka94
3 years ago
7

Need help with balancing equations!

Chemistry
2 answers:
kirill [66]3 years ago
8 0

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the balanced chemical equation for given reaction ~

\sf Fe_2O_3 (s) +3 \:  CO (g) =2 \:  Fe(l) + 3\: CO_2 (g)

As we can see, the Coefficient of Fe (l) is 2

shusha [124]3 years ago
4 0

Answer:

Fe2O3 + 3CO → 2Fe + 3CO2

Explanation:

the numbers in front are the numbers you need

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A chemistry teacher adds 50.0 mL of 1.50 M H2SO4 solution to 200 mL of water. What is the concentration of the final solution? U
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Hello!

The concentration of the final solution when a<span> chemistry teacher adds 50.0 mL of 1.50 M H2SO4 solution to 200 mL of water is 0,3 M

To calculate that, you'll need to use the dilution law, where initial and final concentrations are M1 and M2 respectively, and initial and final volumes are V1 and V2, as shown below. Keep in mind that the final volume is the sum of the 200 mL of water and the 50 mL of H</span>₂SO₄ that were added by the teacher. 

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Have a nice day!
6 0
3 years ago
Read 2 more answers
An ore sample is known to contain copper sulfate pentahydrate, CuSO4•5H2O. If a 10.000 g sample of the ore loses 0.8445 g of wat
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As 1 mole of contains 5 moles of water, moles of CuSO₄.5H₂O are:

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The molecular mass of CuSO₄.5H₂O is 249,69g/mol. Thus, mass of 9,38x10⁻³ moles of CuSO₄.5H₂O is:

9,38x10⁻³ moles of CuSO₄.5H₂O × (249,69g / mol) =

<em>2,341g of CuSO₄.5H₂O </em>is the maximum quantity of CuSO₄.5H₂O that could be in the sample.

I hope it helps!

3 0
3 years ago
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