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BabaBlast [244]
3 years ago
5

A 25.00 g solid sample of Ca(OH)2 was added into 1250 mL of 0.400 M HCl aqueous solution. The temperature of the solution was de

creased from 36.6oC to 20.0oC. Assuming Ccal of the reaction is 5.225 kJ/oC, how much heat is involved in the reaction?
Chemistry
1 answer:
daser333 [38]3 years ago
5 0

Answer:

86.735 kJ

Explanation:

Simply multiply the change in temperature by the Ccal;

(36.6 - 20.0)×5.225 = 86.735

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According to the ideal gas equation:

PV=nRT

P = Pressure of the gas = ?

V= Volume of the gas = 25.5 L

T= Temperature of the gas = 13°C = (273+13) K  = 286K

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n=  moles of gas= 1.42

P=\frac{nRT}{V}=\frac{1.42\times 0.0821\times 286}{25.5}=1.31atm=996mmHg      (760mmHg=1atm)

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