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Aleksandr [31]
3 years ago
7

Imagine standing on a bathroom scale and reading your weight. now lift one foot and read your weight again. does the scale read

more, less or the same weight when you are standing on one foot?
Physics
2 answers:
7nadin3 [17]3 years ago
8 0
Less because now there is less force on the scale and you are unbalanced. Therefore the scale will have a lower number then before.

Vedmedyk [2.9K]3 years ago
3 0

Answer:B

Explanation: Because the weight will be greater with one leg lifted up in the air, it will make the weight more.

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A light ray traveling through medium 1, index of refraction n1n1n_1 = 1.75, reaches the interface between medium 1 and medium 2,
horrorfan [7]

Answer:

θ₁ = 35.32°

Explanation:

given,

refractive index of medium 1 = n₁ = 1.75

refractive index of medium 2 = n₂ = 1.24

condition to describe the refracted angle

 \theta_{refracted} + \theta_{reflected}=90^0

 \theta_2 = 90^0-\theta_1...(1)

Using Snell's Law

   n₁ sin θ₁ = n₂ sin θ₂

θ₁ , θ₂ is the angle of incidence and refractive index

n₁. n₂ is the refractive index medium 1 and medium 2

   1.75 x  sin θ₁ = 1.24 x sin θ₂

From equation (1)

   1.75 x  sin θ₁ = 1.24 x sin (90-θ₁)

   1.75 sin θ₁ = 1.24 cos θ₁

      tan θ₁ = 0.708

         θ₁ = 35.32°

Hence, angle of incidence is equal to θ₁ = 35.32°

7 0
3 years ago
What best describes an impulse acting on an object?
Triss [41]
The force on an object use Socratic glad to help ..
8 0
2 years ago
3.88 milligrams is equal to how many centigrams?
Lana71 [14]
1 centigram is equal to 10 milligrams.

Divide 3.88 milligrams by 10 to convert into centigrams.

3.88 / 10 = .388

The answer is .388 centigrams.
3 0
3 years ago
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Two different simple harmonic oscillators have the same natural frequency (f=8.80 Hz) when they are on the surface of the Earth.
bekas [8.4K]

Answer:

8.80 Hz

Explanation:

The frequency of a loaded spring is given by

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

where k and m are the spring constant and the mass of the load respectively. The values of these do not change because they are internal properties of the components of the system.

Hence, the frequency of the vertical spring mass does not change and is 8.80 Hz.

On the other hand, the frequency of the simple pendulum is affected because it is given by

\dfrac{1}{2\pi}\sqrt{\dfrac{g}{l}}

where g and l are acceleration due to gravity and length of the pendulum, respectively. It is thus seen that it depends on g, which changes with location. In fact, the new frequency is given by

f_2 = 8.80\sqrt{\dfrac{1.67}{9.81}}=3.63 \text{ Hz}

3 0
3 years ago
What is the acceleration of a body moving with uniform velocity?
AfilCa [17]

Acceleration is the rate of change of velocity, a body moving with uniform velocity does not possess acceleration at all i.e. acceleration is zero





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