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Gemiola [76]
3 years ago
13

1 kg = 2.2 lbs what is the mass in kilograms

Physics
1 answer:
liberstina [14]3 years ago
8 0
You didn't specify what mass you need to convert.
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the proper execution of suggested physical fitness tests is important inachieving the accuracyof the assessment results of one's
ankoles [38]

Answer:

Regular exercise and physical activity increase muscle strength, bone density, flexibility, and stability. Physical fitness can reduce your risk for and resilience to accidental injuries, especially as you get older.

5 0
3 years ago
Which of the following type of personal debts is usually considered wise and justified? A. credit card purchases of luxuries tha
NeTakaya

Answer:

C. Money to pay off other debts and interest

3 0
3 years ago
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The current in a lamp is 0.5 ampere when it is plugged into a standard wall outlet. What is the resistance of the lamp when it i
lidiya [134]

The resistance of the lamp plugged in to a standard wall outlet with a current of 0.5 amps is 240 Ω (ohms)

Explanation:

In the United States Of America the standard voltage is 120 v and their frequency is 60 Hz

Standard wall outlet voltage is 120 V

The current in the lamp is 0.5 ampere

Resistance (R) = V/ I

      = 120/0.5

      = 240Ω (ohms)

Thus the resistance of the lamp plugged in to a standard wall outlet with a current of 0.5 amps is 240 Ω (ohms).

8 0
3 years ago
Walk in a straight line. Now stop. Did you accelerate? Explain
Brums [2.3K]

Answer;

It's about acceleration, right?

4 0
3 years ago
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The total charge a battery can supply is rated in mA⋅h , the product of the current (in mA ) and the time (in h ) that the batte
natita [175]

Answer: 0.2  hours

Explanation: In order to solve this question we have to considerer that a recargeable battery can supply 1800 mA  in one hour then we have to determine how long could this battery drive current through a long, thin wire of resistance 34 Ω .

Besides, this battery has a voltage of 12 V

so by using the Ohm law we also know that V=R*I,

Fron this we can obtain:

I= V/R= 12 V/ 34 Ω=0.35 A= 350 mA

then considering that this battery can supply 1800 mA in one hour we have this battery can supply 350 mA  in x time in the form:

1hour------- 1800 mA

x hour--------350 mA

time= 350/1800= 0.2 hour

4 0
3 years ago
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