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eduard
3 years ago
7

Water from a fire hose is directed horizontally against a wall at a rate of 69.4 kg/s and a speed of 19.6 m/s. Calculate the mag

nitude of the force exerted on the wall, assuming the water comes to a complete stop when hitting the car, with no splash-back.
Physics
1 answer:
Gnoma [55]3 years ago
5 0

Answer:

Force, |F| = 1360.24 N

Explanation:

It is given that,

Water from a fire hose is directed horizontally against a wall at a rate of 69.4 kg/s, \dfrac{m}{t}=69.4\ kg/s

Initial speed of the water, u = 19.6 m/s

Finally water comes to stop, v = 0

To find,

The magnitude of the force exerted on the wall.

Solution,

Let F is the force exerted on the wall. The product of mass and acceleration is called the force exerted. Using second law of motion to find it as :

F=m\dfrac{v-u}{t}

F=\dfrac{-mu}{t}

F=-69.4\ kg/s\times 19.6\ m/s

|F| = 1360.24 N

So, the magnitude of the force exerted on the wall is 1360.24 N.

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Answer:

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Explanation:

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2 years ago
Biotic factors are the blank and blank part of the ecosystem
True [87]

Abiotic factors are the nonliving physical and chemical components of an ecosystem, while biotic factors are the living components of an ecosystem. Both types of factors affect reproduction and survival

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3 years ago
O How are electricity and magnetism related?
Nataly [62]
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4 years ago
4.2 mol of monatomic gas A interacts with 3.2 mol of monatomic gas B. Gas A initially has 9500 J of thermal energy, but in the p
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Answer:

14657.32 J

Explanation:

Given Parameters ;

Number of moles mono atomic gas A ,   n 1  =  4 .2 mol

Number of moles mono atomic gas B ,   n 2  =  3.2mol

Initial energy of gas A ,   K A  =  9500  J

Thermal energy given by gas A to gas B ,   Δ K  =  600 J

Gas constant   R  = 8.314  J / molK

Let  K B  be the initial energy of gas B.

Let T be the equilibrium temperature of the gas after mixing.

Then we can write the energy of gas A after mixing as

(3/2)n1RT = KA - ΔK

⟹ (3/2) x 4.2 x 8.314 x T = 9500 - 600

T = (8900 x 3 )/(2x4.2x8.314) = 382.32 K

Energy of the gas B after mixing can be written as

(3/2)n2RT = KB + ΔK

⟹ (3/2) x 3.2 x 8.314 x 382.32 = KB + 600

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⟹ KB = 14657.32 J

6 0
3 years ago
2. You decide to lift a 25 kg box to a height of 3 meters. How much work will you do while moving
nadya68 [22]

Answer:

W = 735.75[J]

Explanation:

Work is defined as the product of force by distance. Therefore we can use the following equation.

W=F*d

where:

W = work [J] (units of Joules)

F = force [N] (units of Newtons)

d = distance = 3 [m]

But first, we must determine the force that is equal to the product of mass by gravity (weight of the body).

F=m*g\\F=25*9.81\\F=245.25[N]

W=F*d\\W=245.25*3\\W=735.75[J]

4 0
3 years ago
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