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adell [148]
3 years ago
11

a dragster accelerates from rest to 135 mph in 9 seconds. calculate the dragsters rate of acceleration​

Mathematics
1 answer:
Deffense [45]3 years ago
7 0
The answer: the amount of the dragsters rate of acceleration is 15
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Prove that an = 4^n + 2(-1)^nis the solution to
olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute a_n=4^n+2(-1)^n in the equation a_n=3a_{n-1}+4a_{n-2} the equality is true.

Let's substitute first in the right hand side:

3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})

Now we use the distributive laws. Also, note that (-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n} (this also works when the power is n-2).

=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}

=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}

=4(4^{n-1})-6(-1)^{n}+8(-1)^{n}=4^n+2(-1)^n=a_n

then the sequence solves the recurrence relation.

4 0
3 years ago
What is the gcf of 12 and 36
timofeeve [1]
The gcf would be 12 because both 12 and 36 can be divided by 12 and it is the highest number
4 0
3 years ago
All muntiple of 5 is an odd number true proposition?​
Natasha2012 [34]

a of 5 is 2.5 b of 5 is 2.5 although 5+5=10 = 2.5×4 =10 (even) x of 5 is odd and y of 5 is even

Therefore, its false;)

5 0
3 years ago
Paul owes Paula 35 cents and has a pocket full of 5-cent coins, 10-cent coins, and 25-cent coins that he can use to pay her. Wha
kykrilka [37]
So, what is the case in which he uses the least coins? can he use 1 coin? no, there isn't a 35 cent coin. can he use 2 coins? yes! he can use 25+10 cent coins!

now, the largest number of coins means the coins of the smallest value: so using only 5 cent coins. How many would this be?

we have to divide:

35/5=7

so we would use 7 coins.

And the difference is 5: 7-2 is 5.
6 0
3 years ago
PLS HELP ME UNDERSTAND THIS
Romashka-Z-Leto [24]

Answer:

Exact form: 44/15

Decimal form: 2.93 repeating

Mixed number form: 2 14/15

Step-by-step explanation:

6 0
2 years ago
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