Question

What volume will 6.745g of neon gas occupy at standard temp and pressure?

Answer 1

Explanation:

It is given that mass of neon is 6.745 g and molar mass of neon is 20 g/mol.

Hence, calculate the number of moles as follows.

            No. of moles = $\frac{mass}{\text{molar mass}}$

Putting the given values into the above formula as follows.

          No. of moles = $\frac{mass}{\text{molar mass}}$

                                = $\frac{6.745 g}{20 g/mol}$

                                = 0.34 mol

Also, at standard conditions value of temperature is 298 K and pressure is 1 atm.

So, putting the values into ideal gas equation and calculate the value of volume as follows.

                          PV = nRT

          $1 atm \times V = 0.34 mol \times 0.082 L atm/mol K /times 298 K$

                  V = 8.31 L

Thus, we can conclude that volume of given neon gas is 8.31 L.

Answer 2

First, multiply the mass by the molar mass of neon to find out how many moles of neon there are. Then, multiply by 22.4 to find out how many liters there are.

6.745g Ne x 1 mole Ne/20 g Ne x 22.4 L/1 mole Ne = 7.5544 L