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marta [7]
3 years ago
5

What volume will 6.745g of neon gas occupy at standard temp and pressure?

Chemistry
2 answers:
Snezhnost [94]3 years ago
6 0

Explanation:

It is given that mass of neon is 6.745 g and molar mass of neon is 20 g/mol.

Hence, calculate the number of moles as follows.

            No. of moles = \frac{mass}{\text{molar mass}}

Putting the given values into the above formula as follows.

          No. of moles = \frac{mass}{\text{molar mass}}

                                = \frac{6.745 g}{20 g/mol}

                                = 0.34 mol

Also, at standard conditions value of temperature is 298 K and pressure is 1 atm.

So, putting the values into ideal gas equation and calculate the value of volume as follows.

                          PV = nRT

          1 atm \times V = 0.34 mol \times 0.082 L atm/mol K /times 298 K

                  V = 8.31 L

Thus, we can conclude that volume of given neon gas is 8.31 L.

Thepotemich [5.8K]3 years ago
4 0
First, multiply the mass by the molar mass of neon to find out how many moles of neon there are. Then, multiply by 22.4 to find out how many liters there are.

6.745g Ne x 1 mole Ne/20 g Ne x 22.4 L/1 mole Ne = 7.5544 L
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Write the two balanced equations, one for the incomplete combustion of methane (to form carbon monoxide and water vapor), and an
kompoz [17]

Answer:

2CH_{4(g)} +3O_{2(g)} -->2CO(g)+4H_{2}O_{(g)}\\CH_{4(g)} +2O_{2(g)} -->CO_{2(g)} +2H_{2}O_{(g)} \\

Explanation:

2CH_{4(g)} +3O_{2(g)} -->2CO(g)+4H_{2}O_{(g)}\\CH_{4(g)} +2O_{2(g)} -->CO_{2(g)} +2H_{2}O_{(g)} \\

The incomplete combustion of alkanes, and other fuels actually, happens when there is a limited supply of oxygen. Instead of the fuel burning completely to produce carbon dioxide, it produces carbon monoxide instead.

This gas is harmful to jumans because it combines with haemoglobin in lood and takes up space that belongs to oxygen which can lead to suffocation or even death

6 0
3 years ago
A solution was prepared by mixing 50.0 g
frez [133]

Answer:

4.78 %.

Explanation:

<em>mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.</em>

<em></em>

<em>mass % = (mass of solute/mass of solution) x 100.</em>

<em></em>

mass of MgSO₄ = 50.0 g,

mass of water = d.V = (0.997 g/mL)(1000.0 mL) = 997.0 g.

mass of the solution = mass of water + mass of MgSO₄ = 997.0 g + 50.0 g = 1047.0 g.

<em>∴ mass % = (mass of solute/mass of solution) x 100</em> = (50.0 g/1047.0 g) x 100 = <em>4.776 % ≅ 4.78 %.</em>

4 0
4 years ago
The elemental analysis of an organic solid extracted from gum arabic (a gummy substance used in adhesives, inks, and pharmaceuti
Evgesh-ka [11]

Answer:

The molar mass of the organic solid is 120.16 g/mol.

The molecular formula of an organic solid is C_4H_8O_4

Explanation:

Let the molecular mass of an organic solid be C_xH_yO_z

\Delta T_b=K_b\times m

Delta T_b=K_b\times \frac{\text{Mass of solid}}{\text{Molar mass of solid}\times \text{Mass of diphenyl  in Kg}}

where,

\Delta T_f =Elevation in boiling point = =1.5^oC

Mass of organic solid= 0.561 g

Mass of diphenyl = 24.9 g = 0.0249 kg (1 kg = 1000 g)

K_b = boiling point constant = 8.00 °C/m

m = molality

Now put all the given values in this formula, we get

1.5^oC=8.00 ^oC/m\times \frac{0.561 g}{\text{Molar mass of solid}\times 0.0249 kg}

{\text{Molar mass of solid}}=120.16 g/mol

\%=\frac{\text{Number of atoms}\times \text{mass of an atom}}{\text{molas mass of compound}}\times 100

Percentage of carbon in an organic solid = 40.0%

40\%=\frac{x\times 12 g/mol}{120.16 g/mol}\times 100

x = 4.0

Percentage of hydrogen in an organic solid = 6.7%

6.7\%=\frac{y\times 1 g/mol}{120.16 g/mol}\times 100

y = 8.0  

Percentage of hydrogen in an organic solid = 6.7%

53.3\%=\frac{x\times 12 g/mol}{120.16 g/mol}\times 100

y = 4.0

The molecular formula of an organic solid is C_4H_8O_4

8 0
3 years ago
Which statement is correct abound chemical bonding in BF3 molecule O The molecule is not stable and hardly exist since the numbe
IceJOKER [234]

The molecule is stable and can exist even though the number of valence electrons around central atom in the molecule are less than 8.

<h3>Is BF3 molecule stable or not?</h3>

BF3 molecule is a stable molecule because all the electrons present in the outermost shell of boron are covalently bonded with fluorine. Boron in BF3, three bonds is the maximum possible because boron only has 3 electrons to share.

So we can conclude that the molecule is stable and can exist even though the number of valence electrons around central atom in the molecule are less than 8.

Learn more about molecule here: brainly.com/question/26044300

#SPJ1

5 0
2 years ago
Answer pls ASAP will mark the brainliest
harina [27]
First one……………………………….
6 0
3 years ago
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