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2 years ago

If flowers begin to wilt is there anything that can be done to save them

Chemistry

2 answers:

inysia [295]2 years ago

8 0

There cant be anything done to save them sorry<span />

almond37 [142]2 years ago

4 0

Feed Them , And Buy Fertilizer To Give Them Extra Nutrients

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Select ALL correct answers. The contact force is caused by: A. Atoms randomly crashing into each other B. The charged particles

Inessa [10]

Answer:

A. Atoms randomly crashing into each other

E. The force of one object pushing against the force of another object.

Explanation:

Forces can be classified into two categories based upon the the mode of transfer or application:

1. Contact forces

2. Non-contact forces

Contact forces are the ones which require the physical contact of the matter to get transferred and tend to create the affect. Whereas non-contact forces have the field property which transfers the affect of force from one point to another without any physical contact of the matter or the medium.

Atoms crashing onto each other have some mass and velocity which upon collision impacts the other atoms exerts a contact force.
The interaction between the charged particles due to their charges is always due to the electric field be it electron or proton, be it within an atom or out of an atom.
The force between any two objects pushing or pulling each other is also possible only due to contact.

6 0

3 years ago

How many molecules of nitrogen gas are found in 0. 045 L of nitrogen gas at STP?

stepan [7]

Answer:

See below

Explanation:

.045 liter / 22.4 l / mole * 6.022 x 10^23 molecules/mole * 2 atoms/molecule =

( * 2 becuase nitrogen gas is diatomic)

7 0

1 year ago

II. Ionic Equations

mario62 [17]

Answer:

Complete ionic: $\begin{aligned}& \rm 2\, Ag^{+}\, (aq) + 2\, {NO_3}^{-} \, (aq) + Ca^{2+}\, (aq) + 2\, Cl^{-}\, (aq) \\ & \rm \to 2\, AgCl\, (s) + Ca^{2+}\, (aq) + 2\, {NO_3}^{-}\, (aq)\end{aligned}$ .

Net ionic: $\begin{aligned}& \rm Ag^{+}\, (aq) + Cl^{-}\, (aq) \to AgCl\, (s)\end{aligned}$ .

Explanation:

Start by identifying species that exist as ions. In general, such species include:

Soluble salts.
Strong acids and strong bases.

All four species in this particular question are salts. However, only three of them are generally soluble in water: $\rm AgNO_3$ , $\rm CaCl_2$ , and $\rm Ca(NO_3)_2$ . These three salts will exist as ions:

Each $\rm AgNO_3\, (aq)$ formula unit will exist as one $\rm Ag^{+}$ ion and one $\rm {NO_3}^{-}$ ion.
Each $\rm CaCl_2$ formula unit will exist as one $\rm Ca^{2+}$ ion and two $\rm Cl^{-}$ ions (note the subscript in the formula $\rm CaCl_2\!$ .)
Each $\rm Ca(NO_3)_2$ formula unit will exist as one $\rm Ca^{2+}$ and two $\rm {NO_3}^{-}$ ions.

On the other hand, $\rm AgCl$ is generally insoluble in water. This salt will not form ions.

Rewrite the original chemical equation to get the corresponding ionic equation. In this question, rewrite $\rm AgNO_3$ , $\rm CaCl_2$ , and $\rm Ca(NO_3)_2$ (three soluble salts) as the corresponding ions.

Pay attention to the coefficient of each species. For example, indeed each $\rm AgNO_3\, (aq)$ formula unit will exist as only one $\rm Ag^{+}$ ion and one $\rm {NO_3}^{-}$ ion. However, because the coefficient of $\rm AgNO_3\, (aq)\!$ in the original equation is two, $\!\rm AgNO_3\, (aq)$ alone should correspond to two $\rm Ag^{+}\!$ ions and two $\rm {NO_3}^{-}\!$ ions.

Do not rewrite the salt $\rm AgCl$ because it is insoluble.

$\begin{aligned}& \rm 2\, Ag^{+}\, (aq) + 2\, {NO_3}^{-} \, (aq) + Ca^{2+}\, (aq) + 2\, Cl^{-}\, (aq) \\ & \rm \to 2\, AgCl\, (s) + Ca^{2+}\, (aq) + 2\, {NO_3}^{-}\, (aq)\end{aligned}$ .

Eliminate ions that are present on both sides of this ionic equation. In this question, such ions include one unit of $\rm Ca^{2+}$ and two units of $\rm {NO_3}^{-}$ . Doing so will give:

$\begin{aligned}& \rm 2\, Ag^{+}\, (aq) + 2\, Cl^{-}\, (aq) \to 2\, AgCl\, (s)\end{aligned}$ .

Simplify the coefficients:

$\begin{aligned}& \rm Ag^{+}\, (aq) + Cl^{-}\, (aq) \to AgCl\, (s)\end{aligned}$ .

7 0

2 years ago

How much money will it cost to drive a school bus 94.00 miles if it gets 6.500 miles per gallon and gas costs $2.459/gallon?

bagirrra123 [75]

Answer:

It will cost $35.5602

Explanation:

$2.459 /6.5 (mpg) = 0.3783 (cents per mile)

$0.3783 (cost per mile) * 94 (total miles) = $35.5602 total

6 0

1 year ago

Iron (III) nitrate (Fe(NO3)3) solution reacts with sodium hydroxide (NaOH) solution to form a

sveticcg [70]

Answer:

Fe(NO3)3 + 3 NaOH ===》Fe(OH)3 + 3 NaNO3

7 0

2 years ago