The magnitude of dispersion forces in Br2 is greater than the magnitude of dispersion forces in Cl2.
Atomic radius decreases across the period but increases down the group. As more shells are added to the atom, the repulsion between electrons increases. Across the group, more electrons are added without increase in the number of shell hence atomic radius decreases across the period due to increase in the size of the nuclear charge. Therefore, the atomic radius of Li is larger than that of Be.
Ionization energy is a periodic trend that increases across the period but decreases down the group. Since the outermost electron is further from the nucleus due to screening of inner electrons, ionization energy decreases down the group. Across the period, the size of the nuclear charge increases hence ionization energy increases across the period.
For K, the second electron is removed from an inner shell which requires a very large amount of energy. In Ca, the second electron is removed from the valence shell which requires a lesser amount of energy. Therefore, the second ionization energy of K is greater than the second ionization energy of Ca.
The carbon to carbon bond in C2H4 is a double bond which has a greater bond enthalpy than the single bond in C2H6. As such, the carbon to carbon bond in C2H4 has a greater bond energy than the carbon to carbon bond in C2H6.
The boiling point of Cl2 is lower than the boiling point of Br2 because Br2 is larger than Cl2 hence the magnitude of dispersion forces in Br2 is greater than the magnitude of dispersion forces in Cl2.
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Answer:
I think you mean 'specific heat'. Well, the exact definition is, ' It is defined as the amount of thermal energy required to raise the temperature of a unit mass (1kg) of a substance by I K or I (degree) C.
Explanation:
Answer:
Al(NO₃)₃ + (NH₄)₃PO₄ —> AlPO₄ + 3NH₄NO₃
The coefficients are: 1, 1, 1, 3
Explanation:
__Al(NO₃)₃ + __(NH₄)₃PO₄ —> __AlPO₄ + __NH₄NO₃
The above equation can be balance as illustrated below:
Al(NO₃)₃ + (NH₄)₃PO₄ —> AlPO₄ + NH₄NO₃
There are 12 atoms of H on the left side and 4 atoms on the right side. It can be balance by writing 3 before NH₄NO₃ as shown below:
Al(NO₃)₃ + (NH₄)₃PO₄ —> AlPO₄ + 3NH₄NO₃
Now the equation is balanced.
The coefficients are: 1, 1, 1, 3
Answer:
Explanation:
1)
Given data:
Initial volume of balloon = 0.8 L
Initial temperature = 12°C ( 12+273= 285 K)
Final temperature = 300°C (300+273 = 573 K)
Final volume = ?
Solution:
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 0.8 L .573 K / 285 K
V₂ = 458.4 L / 285
V₂ = 1.61 L
2)
Initial pressure = 204 kpa
Initial temperature = 29°C ( 29 + 273 = 302 K)
Final temperature = ?
Final pressure = 300 kpa
Solution:
P₁/T₁ = P₂/T₂
T₂ = T₁P₂/P₁
T₂ = 302 K . 300 kpa / 204 kpa
T₂ = 90600 K/ 204
T₂ = 444.12 K
3)
Given data:
Initial volume = 14 L
Initial pressure = 2.1 atm
Initial temperature = 100 K
Final temperature = 450 K
Final volume = ?
Final pressure = 1.2 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 2.1 atm × 14 L × 450 K / 100 K × 1.2 atm
V₂ = 13230 L / 120
V₂ = 110.25 L
The kinetic molecular theory<span> of gases is stated in the following four </span>principles<span>: The space between gas </span>molecules<span> is much larger than the </span>molecules<span> themselves. Gas </span>molecules<span> are in constant random motion. The average </span>kinetic<span> energy is determined solely by the temperature.
I got this from my notes from my chemistry class last semester
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