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Ivahew [28]
3 years ago
11

Two cars are travelling side by side down a straight road in opposite directions.Both cars are travelling at a speed of 22m/s. W

hat is their relative speed ?
Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

Their relative speed is 44 m/s

Explanation:

* <em>Lets explain what is the relative speed</em>

<u><em>Relative motion</em></u> is the change in position with time of one object

compared to another object.

If objects moving in the <em>same direction</em> towards, or away from, each

other, then relative speed is ⇒ <em>fastest speed – slowest speed</em>

If objects moving in <em>opposite directions</em> towards, or away from, each

other, then relative speed is ⇒ <em>the sum of the two speeds together</em>

* Lets solve the problem

Two cars are travelling side by side down a straight road in opposite

directions.

Both cars are travelling at a speed of 22 m/s

The two cars are travelling in opposite direction, then the relative

speed is the sum of their speed together

They are travelling at the same speed 22 m/s.

Then their relative speed = 22 + 22= 44 m/s

* <em>Their relative speed is 44 m/s</em>

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A force of 20.0 N is applied to a 3.00 kg object for 4.00 seconds. Calculate the impulse experienced by the object.​
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Answer:

Impulse = 80Ns

Explanation:

Given the following data;

Mass = 3kg

Force = 20N

Time = 4 seconds

To find the impulse experienced by the object;

Impulse = force * time

Impulse = 20*4

Impulse = 80Ns

Therefore, the impulse experienced by the object is 80 Newton-seconds.

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When two license plates are issued they need to be attached to the _________ of the vehicle they were issued for.
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Answer:

Front and the rear bumpers.

Explanation:

When two license plates are issued they need to be attached to the Front and the rear bumpers of the vehicle they were issued for.

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3 years ago
How is Newton’s 3rd law in baseball?
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What is the word we use for when we repeat the same thing more than once in an experiment?
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3 years ago
Read 2 more answers
A person of mass 55 kg swings on a rope length 4 m from rest (when the rope makes an angle of 30 degrees with the vertical) and
vovangra [49]

Answer:

θ = 19.66°

Explanation:

To determine the angle that the rope makes with the vertical for the two people, you first take into account the potential energy of the first person before he swings on the rope:

U=mgh

h: distance to the ground

g: gravitational acceleration = 9.8m/s^2

m: mass of the first person = 55 kg

In the image attache below you can notice that the height h is:

h=4-4cos(30\°)=0.53m

Then, the potential energy is:

U=(55kg)(9.8m/s^2)(0.53m)=285.67J

When the first person picks up the second person (when the rope is exactly vertical), all the potential energy becomes kinetic energy. Next, when both people reaches the maximum height h' the energy must be equal to the initial potential energy of the first person:

U'=(m_1+m_2)gh'=285.67\ J

From the previous equation you can get h':

h'=\frac{285.67J}{(55kg+70kg)(9.8m/s^2)}=0.2332m

Finally, you obtain the angle between the rope at the height h,' and the vertical, by calculating the following:

h'=4-4cos(\theta)\\\\\theta=cos^{-1}(\frac{4-h'}{4})=cos^{-1}(\frac{4-0.2332}{4})=19.66\°

hence, the angle between the rope and the vertical, when the two people are in the rope is 19.66°

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3 years ago
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