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3 years ago

When learning a new exercise what is the first thing you should focus on?

Physics

2 answers:

Allisa [31]3 years ago

7 0

Answer:

The answer is B if your form is correct

Brums [2.3K]3 years ago

3 0

Answer:

If your form is correct (b)

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The amount of energy that must be absorbed or lost to raise or lower the temperature of 1 g of liquid water by 1°c _____.

Fiesta28 [93]

Answer:

4.2 J

Explanation:

Specific heat capacity: This is defined as the amount of a heat required to rise a unit mass of a substance through a temperature of 1 K

From specific heat capacity,

Q = cmΔt.............................. Equation 1

Where Q = amount of energy absorbed or lost, c = specific heat capacity of water, m = mass of water, Δt = Temperature rise.

Given: m = 1 g = 0.001 kg, Δt = 1 °C

Constant : c = 4200 J/kg.°C

Substitute into equation 1

Q = 0.001×4200(1)

Q = 4.2 J.

Hence the energy absorbed or lost = 4.2 J

6 0

3 years ago

An electrical heater 100 mm long and 5 mm in diameter is inserted into a hole drilled normal to the surface of a large block of

slega [8]

Answer:

$T_{1}=94.9^{o}C$

Explanation:

Given data

length=100mm

Diameter=5mm

Thermal conductivity=5 W/m.K

Power=50 W

Temperature=25°C

The temperature of heater surface follows from the rate equation written as:

$T_{1}=T_{2}+\frac{q}{kS}$

Where S can be estimated from the conduction shape factor for a vertical cylinder in semi infinite medium

$S=\frac{2\pi L}{ln(\frac{4L}{D} )} \\$

Substitute the given values

$S=\frac{2\pi (0.1m)}{ln[\frac{4*0.1m}{0.005m} ]}\\ S=0.143m$

The temperature of heater is then:

$T_{1}=25^{o}C+\frac{50W}{5W/m.K*0.143m} \\T_{1}=94.9^{o}C$

The temperature reached by the heater when dissipating 50 W with the surface of the block at a temperature of 25°C.

$T_{1}=94.9^{o}C$

5 0

3 years ago

I need help on this one please

klio [65]

Lithium shares more properties with Sodium, because they have the same number of valence electrons (one). Choice 1 is correct. Hope this helps!

4 0

3 years ago

A particle moves along a straight line with equation of motion s = f(t), where s is measured in meters and t in seconds. Find th

Rashid [163]

Answer:

The velocity of the particle = -1.92 m/s

The speed of the particle = 5.72 m/s

Explanation:

Given equation of motion;

$f(t) = 18 \ + \ \frac{48}{t} \ + \ 1$

Velocity is defined as the change in displacement with time.

$V = \frac{df(t)}{dt} = -\frac{48}{t^2} \\\\at \ t = 5 \ s\\\\V = -\frac{48}{5^2} = \frac{-48}{25} = - 1.92 \ m/s$

The distance traveled by the particle in 5 s:

$s = f(5) = 18 + \frac{48}{5} + 1\\\\s= 28.6 \ m$

The speed of the particle when t = 5s

$Speed = \frac{28.6}{5} = 5.72 \ m/s$

6 0

3 years ago

A uniform bar 12 m long has a mass 20 kg. A 10 kg pointed mass is attached to one end of the rod. Now the position of COM of the

user100 [1]

Answer:

Explanation:

7 0

3 years ago