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mezya [45]
3 years ago
12

Surface winds on Earth are primarily caused by differences in

Physics
2 answers:
Likurg_2 [28]3 years ago
6 0

Surface winds on Earth are primarily caused by differences in Air density due to unequal heating of Earth's surface. The answer is letter A. Surface currents are driven by winds that blow in certain patterns. They are caused by the Earth’s spin and the Coriolis effect. Evaporation adds water to the atmosphere. It is the change from liquid to gas wherein liquid molecules tends to go the gas phase and increases the number of molecules. 

Explanation:

Causes of Different Pressure on the Earth's Exterior. Differences in pressures across the cover of the Earth are fundamentally produced by irregular heating of the surface by the Sun.

mylen [45]3 years ago
4 0

Surface winds on Earth are primarily caused by differences in Air density due to unequal heating of Earth's surface. The answer is letter A. Surface currents are driven by winds that blow in certain patterns. They are caused by the Earth’s spin and the Coriolis effect. Evaporation adds water to the atmosphere. It is the change from liquid to gas wherein liquid molecules tends to go the gas phase and increases the number of molecules. 

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When there is faster-moving water between two ships, are the ships sucked together or pushed together? explain?
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Which letter represents the location of the<br> resister in this diagram?<br> A<br> B<br> C<br> D
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Answer:

The letter B is the letter that represents the location of the resister in the diagram.

Explanation:

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To calculate the change in kinetic energy, you must know the force as a function of _______. The work done by the force causes t
aliya0001 [1]

To calculate the change in kinetic energy, you must know the force as a function of position. The work done by the force causes the kinetic energy change

Explanation:

The work-energy theorem states that the change in kinetic enegy of an object is equal to the work done on the object:

\Delta E_k = W

where the work done is the integral of the force over the position of the object:

W=\int F(x) dx

As we see from the formula, the magnitude of the force F(x) can be dependent from the position of the object, therefore in order to solve correctly the integral and find the work done on the object, it is required to know the behaviour of the force as a function of the position, x.

6 0
3 years ago
A railroad car of mass 2.52 104 kg is moving with a speed of 3.86 m/s. It collides and couples with three other coupled railroad
aleksley [76]

Answer:

a)   v = 2.4125 m / s  , b)  Em_{f} / Em₀ = 0.89

Explanation:

a) This is an inelastic crash problem, the system is made up of the four carriages, so the forces during the crash are internal and the moment is conserved

Initial

          p₀ = m v₁ + 3 m v₂

Final

         p_{f} = (4 m) v

        p₀ =p_{f}

        m (v₁ + 3 v₂) = 4 m v

        v = (v₁ +3 v₂) / 4

Let's calculate

       v = (3.86 + 3 1.93) / 4

       v = 2.4125 m / s

b) the initial mechanical energy is

       Em₀ = K₁ + 3 K₂

       Em₀ = ½ m v₁² + ½ 3m v₂²

       

The final mechanical energy

         Em_{f} = K

         Em_{f} = ½ 4 m v²

The fraction of energy lost is

          Em_{f} / Em₀ = ½ 4m v² / ½ m (v₁² +3 v₂²)

          Em_{f} / Em₀ = 4 v₂ / (v₁² + 3 v₂²)

          Em_{f} / Em₀ = 4 2.4125² / (3.86² + 3 1.93²)

          Em_{f} / em₀ = 23.28 / 26.07

          Em_{f} / Em₀ = 0.89

6 0
3 years ago
Please help on this one?
qwelly [4]

Answer:

D. An image that is smaller than the object and is behind the mirror

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