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nikitadnepr [17]
3 years ago
7

Acceleration increases over time once a force is applied to the object. Given a force of 10.0 Newtons, which mass will have the

greatest acceleration?
Physics
2 answers:
Zolol [24]3 years ago
6 0

Mass is indirectly proportional to acceleration, so, lighter the object greater would be it's acceleration...

A) 0.10 kg is lightest among them, so it's your answer

Alona [7]3 years ago
6 0

<u><em>Answer</em></u> : A) 0.10kg beach ball

<u><em>Explanation</em></u> : Given a force of 10.0 Newtons, which mass will have the greatest acceleration?

0.10 kg beach ball

F=ma

Rearranging for acceleration gives

a=F/m

For the beach ball

a=(10.0 Newtons)/(0.10 kg)

a=100 m/s2

For the brick

a=(10.0 Newtons)/(2.0 kg)= 5 m/s2

For the steel ball

a=(10.0 Newtons)/(5.0 kg)= 2 m/s2

For the bag of feathers

a=(10.0 Newtons)/(10.0 kg)= 1 m/s2

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A 350-g mass is attached to a spring whose spring constant is 64 N/m. Its maximum acceleration is 5.3 m/s2. What is the frequenc
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The frequency of oscillation is 2.153 Hz

What is the frequency of spring?

Spring Frequency is the natural frequency of spring with a weight at the lower end. Spring is fixed from the upper end and the lower end is free.

For the mass-spring system in this problem,

The Frequency of spring is calculated with the equation:

f = \frac{1}{2\pi } \sqrt{\frac{k}{m} }

Where,

f = frequency of spring

k = spring constant = 64 N/m

m = mass attached to spring = 350g = 0.350 kg

a = maximum acceleration = 5.3 m/s^2

Substituting the values in the equation,

f = \frac{1}{2\pi } \sqrt{\frac{64}{0.350} }

f = \frac{1}{2\pi } ( 13.522)

f = 2.1535 Hz

Hence,

The frequency of oscillation is 2.153 Hz

Learn more about frequency here:

<u>brainly.com/question/13978015</u>

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Which part(s) of a hair can be analyzed for nuclear DNA?
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The sound produced by the loudspeaker in the drawing has a frequency of 11999 Hz and arrives at the microphone via two different
const2013 [10]

The speed at which sound travels through the gas in the tube is 719.94m/s

<u>Explanation:</u>

Given:

Frequency, f = 11999Hz

Wavelength, λ = 0.03m

Velocity, v = ?

Sound speed in the tube is calculated by multiplying the frequency v by the wavelength λ.

As the sound loudness changed from a maximum to a minimum, then we know the sound interference in the case changed from constructive interference (the two sound waves are in phase, i.e. peaks are in a line with peaks and so the troughs), to a destructive interference (peaks coinciding with troughs). The least distance change required to cause such a change is a half wavelength distance, so:

λ/2 = 0.03/2

 λ  = 0.06m

We know,

v = λf

v = 0.06 X 11999Hz

v = 719.94m/s

Therefore, the speed at which sound travels through the gas in the tube is 719.94m/s

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