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nikitadnepr [17]
3 years ago
7

Acceleration increases over time once a force is applied to the object. Given a force of 10.0 Newtons, which mass will have the

greatest acceleration?
Physics
2 answers:
Zolol [24]3 years ago
6 0

Mass is indirectly proportional to acceleration, so, lighter the object greater would be it's acceleration...

A) 0.10 kg is lightest among them, so it's your answer

Alona [7]3 years ago
6 0

<u><em>Answer</em></u> : A) 0.10kg beach ball

<u><em>Explanation</em></u> : Given a force of 10.0 Newtons, which mass will have the greatest acceleration?

0.10 kg beach ball

F=ma

Rearranging for acceleration gives

a=F/m

For the beach ball

a=(10.0 Newtons)/(0.10 kg)

a=100 m/s2

For the brick

a=(10.0 Newtons)/(2.0 kg)= 5 m/s2

For the steel ball

a=(10.0 Newtons)/(5.0 kg)= 2 m/s2

For the bag of feathers

a=(10.0 Newtons)/(10.0 kg)= 1 m/s2

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nekit [7.7K]

Answer:

2.62seconds

Explanation:

Speed is defined as the ratio of the distance covered by a body with respect to time.

Speed v = Distance (s)/Time (t)

For a traveling sound wave, the distance between the source of a sound and the reflector is '2S'.

Speed v = 2 × distance (S)/Time (T)

V = 2S/t

2S = vt

Given speed of the wave = 342m/s

Distance covered = 450m

t = 2S/v

t = (2×450)/343

t = 900/343

t = 2.62seconds

It will take him 2.62seconds for him to hear his own voice echo off of the wall.

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2 years ago
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If each of the charges is increased by two times and the distance between them is also increased by two times, the electromagnet
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Answer: The force does not change.

Explanation:

The force between two charges q₁ and q₂ is:

F = k*(q₁*q₂)/r^2

where:

k is a constant.

r is the distance between the charges.

Now, if we increase the charge of each particle two times, then the new charges will be: 2*q₁ and 2*q₂.

If we also increase the distance between the charges two times, the new distance will be 2*r

Then the new force between them is:

F = k*(2*q₁*2*q₂)/(2*r)^2 = k*(4*q₁*q₂)/(4*r^2) = (4/4)*k*(q₁*q₂)/r^2 = k*(q₁*q₂)/r^2

This is exactly the same as we had at the beginning, then we can conclude that if we increase each of the charges two times and the distance between the charges two times, the force between the charges does not change.

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I know that protons and neutrons are located at the center of an atom, so the correct answer is D

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Pachacha [2.7K]

Explanation:

Given that,

Object-to-image distance d= 71 cm

Image distance = 26 cm

We need to calculate the object distance

u -v= d

u=71+26=97\ cm

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Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

put the value into the formula

\dfrac{1}{f}=\dfrac{1}{-26}+\dfrac{1}{97}

\dfrac{1}{f}=-\dfrac{71}{2522}

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(B). Given that,

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Using formula of magnification

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The image is virtual.

Hence, This is the required solution.

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3 years ago
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Tamiku [17]
1
2 4. 5 4 5
+3 0 7. 3 0 0
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line up the decimal points and add.
hope this helps!
4 0
3 years ago
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