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nikitadnepr [17]
3 years ago
7

Acceleration increases over time once a force is applied to the object. Given a force of 10.0 Newtons, which mass will have the

greatest acceleration?
Physics
2 answers:
Zolol [24]3 years ago
6 0

Mass is indirectly proportional to acceleration, so, lighter the object greater would be it's acceleration...

A) 0.10 kg is lightest among them, so it's your answer

Alona [7]3 years ago
6 0

<u><em>Answer</em></u> : A) 0.10kg beach ball

<u><em>Explanation</em></u> : Given a force of 10.0 Newtons, which mass will have the greatest acceleration?

0.10 kg beach ball

F=ma

Rearranging for acceleration gives

a=F/m

For the beach ball

a=(10.0 Newtons)/(0.10 kg)

a=100 m/s2

For the brick

a=(10.0 Newtons)/(2.0 kg)= 5 m/s2

For the steel ball

a=(10.0 Newtons)/(5.0 kg)= 2 m/s2

For the bag of feathers

a=(10.0 Newtons)/(10.0 kg)= 1 m/s2

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The largest hailstone every measured fell in Vivian, Nebraska in 2010. The circumference of that hailstone was 19 inches. Using
Crazy boy [7]

Answer:

6.04788 in

115.82654\ in^3

78.38779 m/s

0.88159 kg

34.55294 J

Explanation:

Circumference is given by

c=2\pi r\\\Rightarrow r=\dfrac{c}{2\pi}\\\Rightarrow r=\dfrac{19}{2\pi}\\\Rightarrow r=3.02394\ in

Diameter is given by

d=2r\\\Rightarrow d=2\times 3.02394\\\Rightarrow d=6.04788\ in

The diameter is 6.04788 in

6.04788\times 2.54=15.3616152\ cm

Volume of sphere is given by

v=\dfrac{4}{3}\pi r^3\\\Rightarrow v=\dfrac{4}{3}\pi 3.02394^3\\\Rightarrow v=115.82654\ in^3

The volume is 115.82654\ in^3

115.82654\times \dfrac{1}{1728}=0.06702\ ft^3

Fall velocity is given by

V=k\sqrt{d}\\\Rightarrow V=20\sqrt{15.3616152}\\\Rightarrow V=78.38779\ m/s

The velocity of the fall will be 78.38779 m/s

Mass is given by

m=\rho v\\\Rightarrow m=29\times 0.06702\\\Rightarrow m=1.94358\ lb

1.94358\ lb=1.94358\times \dfrac{1}{2.20462}=0.88159\ kg

The mass is 0.88159 kg

Kinetic energy is given by

K=\dfrac{1}{2}mv^2\\\Rightarrow K=\dfrac{1}{2}0.88159\times 78.38779\\\Rightarrow K=34.55294\ J

The kinetic energy is 34.55294 J

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