Answer:58.28 N
Explanation:
Given data
Now velocity of jet at height of 2m
equating them
W=
W=
W=58.28 N
Air within a piston cylinder assembly executes a Carnot refrigeration cycle between hot and cold reservoirs at TH=600 K and TC=3
00 K, respectively. The magnitude of the heat transfer rejected to the high temperature reservoir is 250 kJ per kg of air. The pressure at the start of the isothermal expansion is 325 kPa. The air can be modeled as an ideal gas with constant specific heat (k=1.4). For the air as a system, determine
a. (5) the coefficient of performance.
b. (5) the net work input to the cycle in kJ/kg.
c. (10) the Pv and Ts diagrams for the cycle with arrows showing the directions of the processes.
You may answer parts (a) and (b) in the response box. Part (c) and your calculations supporting.(a) and (b) must be included in your uploaded response file.
a. (5) the coefficient of performance.
b. (5) the net work input to the cycle in kJ/kg.
c. (10) the Pv and Ts diagrams for the cycle with arrows showing the directions of the processes.
You may answer parts (a) and (b) in the response box. Part (c) and your calculations supporting.(a) and (b) must be included in your uploaded response file.
1 answer:
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Answer:
a) | v2 | , β2 ( load, bus voltage at bus 2 )
p1 , q1 ( slack, bus power at bus 1 )
b) q2 , β2
p1 and q1 ( slack, bus power at bus 1 )
Explanation:
Attached below is a schematic representation of the solution
<u>a) Identify the variables in the solution vector assume Bus 2 is a load bus</u>
The specified parameters are ; P2 and q2
while | v2 | and β2 are not specified
given that bus 2 is a load bus, bus 1 is a slack bus with ; | v1 | and β1 been specified while p1 and q1 are not specified
<em>Hence the variables in the solution </em>
<em>= | v2 | , β2 ( load, bus voltage at bus 2 )</em>
<em> p1 , q1 ( slack, bus power at bus 1 ) </em>
<u>b) Identify the variables in the solution vector ( assume Bus 2 is a PV bus )</u>
specified at Bus 2 are ; | p2 | , | v2 |
unspecified : q2 , β2
Bus 1 ( still a slack bus )
specified parameter : | v1 | and β1
unspecified : p1 and q1
<em>Hence the variables in the solution </em>
<em>= q2 , β2 </em>
<em> p1 and q1 ( slack, bus power at bus 1 ) </em>
Answer:
The fluid level difference in the manometer arm = 22.56 ft.
Explanation:
Assumption: The fluid in the manometer is incompressible, that is, its density is constant.
The fluid level difference between the two arms of the manometer gives the gage pressure of the air in the tank.
And P(gage) = ρgh
ρ = density of the manometer fluid = 60 lbm/ft³
g = acceleration due to gravity = 32.2 ft/s²
ρg = 60 × 32.2 = 1932 lbm/ft²s²
ρg = 1932 lbm/ft²s² × 1lbf.s²/32.2lbm.ft = 60 lbf/ft³
h = fluid level difference between the two arms of the manometer = ?
P(gage) = 9.4 psig = 9.4 × 144 = 1353.6 lbf/ft²
1353.6 = ρg × h = 60 lbf/ft³ × h
h = 1353.6/60 = 22.56 ft
A diagrammatic representation of this setup is presented in the attached image.
Hope this helps!
