Answer:
15625 moles of methane is present in this gas deposit
Explanation:
As we know,
PV = nRT
P = Pressure = 230 psia = 1585.79 kPA
V = Volume = 980 cuft = 27750.5 Liters
n = number of moles
R = ideal gas constant = 8.315
T = Temperature = 150°F = 338.706 Kelvin
Substituting the given values, we get -
1585.79 kPA * 27750.5 Liters = n * 8.315 * 338.706 Kelvin
n = (1585.79*27750.5)/(8.315 * 338.706) = 15625
Answer:
a) 28 stations
b) Rp = 21.43
E = 0.5
Explanation:
Given:
Average downtime per occurrence = 5.0 min
Probability that leads to downtime, d= 0.01
Total work time, Tc = 39.2 min
a) For the optimum number of stations on the line that will maximize production rate.
Maximizing Rp =minimizing Tp
Tp = Tc + Ftd
At minimum pt. = 0, we have:
dTp/dn = 0
Solving for n²:
The optimum number of stations on the line that will maximize production rate is 28 stations.
b) 
Tp = 1.4 +1.4 = 2.8
The production rate, Rp =
The proportion uptime,
Answer:
<em>A stable ride</em>
Explanation:
A Catamaran hull is a form of sea craft invented by the Austronesian peoples, the invention of the Catamaran hull enabled these people to sail across the sea in their expansion to the islands of the Indian and Pacific Oceans. Catamaran has multiple hulls, usually two parallel hulls of equal size. This geometric feature gives the craft an increased stability because,<em> it derives extra stability from its wide beam, in the place of a ballasted keel employed in a regular monohull sailboat. </em>A Catamaran hull will require four times the force needed to capsize it, when compared to an equivalent monohull.
Answer:
the MTTF of the transceiver is 50.17
Explanation:
Given the data in the question;
failure modes = 0.1 failure per hour
system reliability = 0.85
mission time = 5 hours
Now, we know that the reliability equation for this situation is;
R(t) = [ 1 - ( 1 - 
)³] 
so we substitute
R(5) = [ 1 - ( 1 - 
)³] 
= 0.85
[ 1 - ( 1 - 
)³] = 0.85
[ 1 - ( 0.393469 )³] = 0.85
[ 1 - 0.06091 ] = 0.85
0.9391 = 0.85
= 0.85 / 0.9391
= 0.90512
MTTF = 5 / -ln( 0.90512 )
MTTF = 50.17
Therefore, the MTTF of the transceiver is 50.17
Answer: they would be 300 miles from the station.
Explanation:
At the point where both trains meet, they would have covered the same distance.
Let t represent the time spent by the first train in covering this distance.
Distance = speed × time
The first train leaves the station and travels north at 60km/hr.
Distance covered by the first train is
60 × t = 60t
Two hours later, a second train leaves on a parallel track and travels north at 100km/hr. Time spent by the second train in covering this distance is (t - 2) hours
Distance covered by the second train is
100(t - 2) = 100t - 200
Since both trains covered the same distance, then
100t - 200 = 60t
100t - 60t = 200
40t = 200
t = 200/40
t = 5 hours
The distance that they would be from the station is
60 × 5 = 300 miles
