Answer: Because if something goes wrong while you are flying it it will crash
Explanation:
Answer:
b). Occurs at the outer surface of the shaft
Explanation:
We know from shear stress and torque relationship, we know that

where, T = torque
J = polar moment of inertia of shaft
τ = torsional shear stress
r = raduis of the shaft
Therefore from the above relation we see that

Thus torsional shear stress, τ is directly proportional to the radius,r of the shaft.
When r= 0, then τ = 0
and when r = R , τ is maximum
Thus, torsional shear stress is maximum at the outer surface of the shaft.
Answer:
Option A - fail/ not fail
Explanation:
For this given problem, if the yield strength is now 45 ksi, using Distortion Energy Theory the material will _fail______ and using the Maximum Shear Stress Theory the material will ___not fail_______
Answer:
7.07%
Explanation:
Thermal efficiency can be by definition seen as the ratio of the heat utilized by a heat engine to the total heat units in the fuel consumed.
We will determine the thermal efficiency of the given problem at the attached file.
Answer:
(b) Given the Weibull parameters of example 11-3, the factor by which the catalog rating must be increased if the reliability is to be increased from 0.9 to 0.99.
Equation 11-1: F*L^(1/3) = Constant
Weibull parameters of example 11-3: xo = 0.02 (theta-xo) = 4.439 b = 1.483
Explanation:
(a)The Catalog rating(C)
Bearing life:
Catalog rating: 
From given equation bearing life equation,

we Dividing eqn (2) with (1)

The Catalog rating increased by factor of 1.26
(b) Reliability Increase from 0.9 to 0.99

Now calculating life adjustment factor for both value of reliability from Weibull parametres


Similarly

Now calculating bearing life for each value

Now using given ball bearing life equation and dividing each other similar to previous problem

Catalog rating increased by factor of 0.61