Ask question

Ask question

All categories

3 years ago

7

Saturns day is roughly 10 hours. it takes about 30 years for Saturn to return to the same point in space. How do saturns periods

of rotation and revolution compare to Earths?
A) Earths period of rotation and revolution are both shorter
B) Earths period of rotation and revolution are both longer
C) earths period of rotation is longer; Earths period of revolution is shorter
D) Earths period of rotation is shorter; Earths period of revolution is longer

2 answers:

sdas [7]3 years ago

6 0

Earth 24 hours, 365 days, so c

GREYUIT [131]3 years ago

3 0

Answer: The correct answer is option (C).

Explanation:

Duration of 1 day on Earth = 24 hours

Duration of 1 complete revolution of the Earth around the sun:

1 year = 31,536,000 seconds.

Duration of the day on the Saturn = 10 hours = 36,000 seconds

Duration of 1 complete revolution of the Saturn around the sun:

= 10 years = 315,360,000 seconds.

1 earth year = 365 days

1 hour = 60 minutes

1 minutes = 60 seconds

From the given information, we can conclude that duration of the rotation of the earth is longer than the duration of rotation of the Saturn.

Whereas the we can conclude that duration of the revolution of the earth is shorter than the duration of revolution of the Saturn.

Hence, the correct answer is option(C).

You might be interested in

Metals experience plastic deformation when _____. A. Their crystal patterns have been disrupted by stress

zaharov [31]

Answer: Option (A) is the correct answer.

Explanation:

Plastic deformation is the change in shape of an object or metal caused by the load of excess stress.

Thus, metals experience plastic deformation when their crystal patterns have been disrupted by stress.

When stress is provided to the metal then their crystal pattern gets deformed resulting in change of shape of the metal. Plastic deformation is a permanent deformation.

5 0

3 years ago

Identify the type of igneous rock that is formed when magma cools above Earth's surface?

mylen [45]

Answer: cools down and keeps going

Explanation:

5 0

3 years ago

Explain what makes a covalently bonded molecule polar. Use the molecules of CH4 and CH3F as examples in your explanation.

RideAnS [48]

Answer:

See explanation

Explanation:

The magnitude of electronegativity difference between atoms in a bond determines whether that bond will be polar or not.

If the electronegativity difference between atoms in a bond is about 1.7, the bond is ionic. If the electronegativity difference is greater than 0.4 and less than 1.7, the bond will have a polar covalent character. Lastly, if the electronegativity difference between the bond is less than or equal to 0.4, the covalent bond is non polar.

The electronegativity difference between carbon and hydrogen is about 0.4 which corresponds to a nonpolar covalent bond hence the molecule is nonpolar.

The electronegativity difference between carbon and fluorine is about 1.5 indicating a highly polar bond. This gives CH3F an overall dipole moment thereby making the molecule polar.

8 0

2 years ago

The balanced reaction between aqueous nitric acid and aqueous strontium hydroxide is ________.

Kaylis [27]

<span>d.2HNO3 (aq) + Sr(OH)2 (aq) → 2H2O (l) + Sr(NO3)2(aq)
4H </span>4H
8O 8O
2N 2N
1Sr 1Sr<span>

</span>

3 0

2 years ago

NItrogen in air reacts at high temperature to form NO2 according to the reaction:

Rina8888 [55]

Answer:

The correct answer is option E.

Explanation:

Structures for the reactants and products are given in an aimage ;

Number of double bonds in oxygen gas molecule = 1

Number of double bonds in nitro dioxide gas molecule = 1

Number of single bond in in nitro dioxide gas molecule = 1

Number of triple bonds in nitrogen gas molecule = 1

$N_2+2O_2\rightarrow 2NO_2,\Delta H=?$

$\Delta H=[2 mol\times \Delta H_{f,NO_2}]-[1 mol\times \Delta H_{f,N_2}-2 mol\times \Delta H_{f,O_2}]$

$\Delta H_{f,NO_2}=33.18 kJ/mol$

$\Delta H_{f,N_2}=0$ (pure element)

$\Delta H_{f,O_2}=0$ (pure element )

$\Delta H=2 mol\times 33.18 kJ/mol=66.36kJ=15.86 kcal$

The enthalpy of the given reaction is 15.86 kcal.

6 0

3 years ago