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Effectus [21]
3 years ago
11

List 3 properties of the hair’s cuticle.

Chemistry
1 answer:
Svet_ta [14]3 years ago
4 0
To be honest I really don’t know sorry
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5. Write the two resonance hybrids for the carbocation that would be formed by protonation at C-1 of 2-methyl-1,3-pentadiene. Wi
kupik [55]

Answer:

Follows are the solution to this question:

Explanation:

Please find the complete solution in the attached file.

7 0
3 years ago
What kind of orbital is occupied by the lone pair electrons in caffeine molecule?
Nataly [62]
The middle nitrogen has two sigma bonds and one pi bond. You know that one p orbital is used in the double bond and two sp2 orbitals are involved in the sigma bond. This leaves one sp2 orbital for the lone pair to occupy.
8 0
3 years ago
Based on the information in the table, which of the following arranges the bonds in order of decreasing polarity?
patriot [66]

Polarity is the chemical property based on the electric charge and orientation of the poles. Al−O>H−Br>As−S is arranged in decreasing order of polarity. Thus, option d is correct.

<h3>What is polarity?</h3>

Polarity is a chemical property of the distribution of the electrical charges over their respective atom in the molecule joined by the bonds. The relation between the polarity and the difference in electronegativity is directly proportional.

The electronegativity difference between the elements are:

  • Al−O = 1.8
  • H−Br = 0.8
  • As−S = 0.4

As the electronegativity difference between Al−O = 1.8 is the highest it will have the highest polarity followed by H−Br = 0.8, and As−S = 0.4, with the lowest polarity.

Therefore, option D. Al−O>H−Br>As−S is arranged in decreasing order of polarity.

Learn more about electronegativity here:

brainly.com/question/25217877

#SPJ1

6 0
2 years ago
Red #40 has an acute oral LD50 of roughly 5000 mg dye/1 kg body weight. This means if you had a mass of 1 kg, ingesting 5000 mg
FrozenT [24]

Answer:

350 g dye

0.705 mol

2.9 × 10⁴ L

Explanation:

The lethal dose 50 (LD50) for the dye is 5000 mg dye/ 1 kg body weight. The amount of dye that would be needed to reach the LD50 of a 70 kg person is:

70 kg body weight × (5000 mg dye/ 1 kg body weight) = 3.5 × 10⁵ mg dye = 350 g dye

The molar mass of the dye is 496.42 g/mol. The moles represented by 350 g are:

350 g × (1 mol / 496.42 g) = 0.705 mol

The concentration of Red #40 dye in a sports drink is around 12 mg/L. The volume of drink required to achieve this mass of the dye is:

3.5 × 10⁵ mg × (1 L / 12 mg) = 2.9 × 10⁴ L

8 0
3 years ago
HELP I NEED THIS ASAP<br>ON THE IMAGE​
Sunny_sXe [5.5K]

Answer:

hope you find it helpful

7 0
3 years ago
Read 2 more answers
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