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WITCHER [35]
3 years ago
13

A parallel-plate capacitor is connected to a battery until it is fully charged. Then, the capacitor is disconnected from the bat

tery and connected to two uncharged parallel plates that make up a capacitor. The potential between the plates of the initial capacitor will
Physics
1 answer:
Helga [31]3 years ago
4 0

Answer:

The potential between the plates will decrease.

Explanation:

An insulator is usually placed between the parallel plates and is also called a dielectric because it makes the amount of charge a capacitor can accommodate to increase at a particular potential difference.

Furthermore, the dielectric effect will make the electric field of the charged capacitor which is not connected to a source of supply to decrease.

Now, when the battery is removed, the charge Q remains constant and Capacity C will increase.

Formula for the potential difference is here;

V = Q/C

Since the numerator Q is constant and the denominator C increases, it means the potential difference V will decrease

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Power(P) is the rate at which work is done. Work done (W) is the product of the force applied on the object and the displacement (s) made by the point of application of the force.

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