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ioda
2 years ago
7

Describe what the sun would look like from earth if the entire photosphere were the same temperature as a sunspot?

Physics
1 answer:
vichka [17]2 years ago
8 0

The sun would look like from earth if the entire photosphere were the same temperature as a sunspot then wouldn't see anything from Earth but darkness

The lowest layer of the sun is the photosphere. It is the outer layer of the sun. It is the deepest region of the luminous object. It is composed of convection cells which are called granules . The Sun's photosphere has a temperature between 4,500 and 6,000 K

Sunspots are areas where the magnetic field is about 2,500 times stronger than Earth's, much higher than anywhere else on the Sun.  Because of the strong magnetic field, the magnetic pressure increases while the surrounding atmospheric pressure decreases.

Sunspots tend to occur in pairs that have magnetic fields pointing in opposite directions.  A typical spot consists of a dark region called the umbra, surrounded by a lighter region known as the penumbra.  

The sunspots appear relatively dark because the surrounding surface of the Sun (the photosphere) is about 10,000 degrees F, while the umbra is about 6,300 degrees F.  Sunspots are quite large as an average size is about the same size as the Earth.

If the photosphere were of the same temperature as the sunspot, then we wouldn't see anything from Earth but darkness. We were only able to see and recognize the sunspot because it is surrounded by the visible photosphere.

To learn more about photosphere here

brainly.com/question/3598352

#SPJ4

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The resultant of two forces is 250 N and the same are inclined at 30° and 45° with resultant one on either side calculate the ma
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The two forces are;

1) Force 1 with magnitude of approximately 183.013 N, acting 30° to the left of the resultant force

2) Force 2 with magnitude of approximately 129.41 N acting at an inclination of 45° to the right of the resultant force

Explanation:

The given parameters are;

The (magnitude) of the resultant of two forces = 250 N

The angle of inclination of the two forces to the resultant = 30° and 45°

Let, F₁ and F₂ represent the two forces, we have;

F₁ is inclined 30° to the left of the resultant force and F₂ is inclined 45° to the right of the resultant force

The components of F₁ are \underset{F_1}{\rightarrow} = -F₁ × sin(30°)·i + F₁ × cos(30°)·j

The components of F₂ are \underset{F_2}{\rightarrow} = F₂ × sin(45°)·i + F₂ × cos(45°)·j

The sum of the forces = F₂ × sin(45°)·i + F₂ × cos(45°)·j + (-F₁ × sin(30°)·i + F₁ × cos(30°)·j) = 250·j

The resultant force, R = 250·j, which is in the y-direction, therefore, the component of the two forces in the x-direction cancel out

We have;

F₂ × sin(45°)·i = F₁ × sin(30°)·i

F₂ ·√2/2 = F₁/2

∴ F₁ = F₂ ·√2

∴ F₂ × cos(45°)·j  + F₁ × cos(30°)·j = 250·j

Which gives;

F₂ × cos(45°)·j  + F₂ ·√2 × cos(30°)·j = 250·j

F₂ × ((cos(45°) + √2 × cos(30°))·j = 250·j

F₂ × ((√2)/2 × (1 + √3))·j = 250·j

F₂ × ((√2)/2 × (1 + √3))·j = 250·j

F₂ = 250·j/(((√2)/2 × (1 + √3))·j) ≈ 129.41 N

F₂ ≈ 129.41 N

F₁  = √2 × F₂ = √2 × 129.41 N ≈ 183.013 N

F₁  ≈ 183.013 N

The two forces are;

A force with magnitude of approximately 183.013 N is inclined 30° to the left of the resultant force and a force with magnitude of approximately 129.41 N is inclined 45° to the right of the resultant force.

5 0
3 years ago
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