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ioda
2 years ago
7

Describe what the sun would look like from earth if the entire photosphere were the same temperature as a sunspot?

Physics
1 answer:
vichka [17]2 years ago
8 0

The sun would look like from earth if the entire photosphere were the same temperature as a sunspot then wouldn't see anything from Earth but darkness

The lowest layer of the sun is the photosphere. It is the outer layer of the sun. It is the deepest region of the luminous object. It is composed of convection cells which are called granules . The Sun's photosphere has a temperature between 4,500 and 6,000 K

Sunspots are areas where the magnetic field is about 2,500 times stronger than Earth's, much higher than anywhere else on the Sun.  Because of the strong magnetic field, the magnetic pressure increases while the surrounding atmospheric pressure decreases.

Sunspots tend to occur in pairs that have magnetic fields pointing in opposite directions.  A typical spot consists of a dark region called the umbra, surrounded by a lighter region known as the penumbra.  

The sunspots appear relatively dark because the surrounding surface of the Sun (the photosphere) is about 10,000 degrees F, while the umbra is about 6,300 degrees F.  Sunspots are quite large as an average size is about the same size as the Earth.

If the photosphere were of the same temperature as the sunspot, then we wouldn't see anything from Earth but darkness. We were only able to see and recognize the sunspot because it is surrounded by the visible photosphere.

To learn more about photosphere here

brainly.com/question/3598352

#SPJ4

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A mechanic pushes a 2.30 ✕ 103-kg car from rest to a speed of v, doing 4,800 J of work in the process. During this time, the car
Illusion [34]

The horizontal force applied is  160 N while the velocity is  2.03 m/s.

<h3>What is the speed of the car?</h3>

The work done by the car is obtained as the product of the force and the distance;

W = F x

F = ?

x = 30.0 m

W = 4,800 J

F = 4,800 J/30.0 m

F = 160 N

But F = ma

a = F/m

a = 160 N/2.30 ✕ 10^3-kg

a= 0.069 m/s

Now;

v^2 = u^2 + 2as

u = 0/ms because the car started from rest

v = √2as

v = √2 * 0.069 * 30

v = 2.03 m/s

Learn more about force and work:brainly.com/question/758238

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5 0
2 years ago
If a car is moving to the left with constantvelocity, one can conclude thatthere mustbe no forces applied to the car.the netforc
Allisa [31]

Answer:

the net force applied to the car is zero.

Explanation:

According to Newton's second law, the acceleration of an object (a) is directly proportional to the net force applied (F):

a=\frac{F}{m}

where m is the object's mass.

In this problem, the car is moving with constant velocity: this means that the acceleration is zero, a = 0. Therefore, according to the previous equation, the net force must also be zero: F = 0. So, the correct answer is

the net force applied to the car is zero.

3 0
4 years ago
In a simple electric circuit, ohm's law states that v=irv=ir, where vv is the voltage in volts, ii is the current in amperes, an
Tju [1.3M]
We take the derivative of Ohm's law with respect to time: V = IR
Using the product rule:
dV/dt = I(dR/dt) + R(dI/dt)
We are given that voltage is decreasing at 0.03 V/s, resistance is increasing at 0.04 ohm/s, resistance itself is 200 ohms, and current is 0.04 A. Substituting:
-0.03 V/s = (0.04 A)(0.04 ohm/s) + (200 ohms)(dI/dt)
dI/dt = -0.000158 = -1.58 x 10^-4 A/s
8 0
4 years ago
Which best explains how an object at rest deep in space and far from any massive body behaves compared to an object in free fall
7nadin3 [17]

Answer: They behave the same because, according to the principle of equivalence, the laws of physics work the same in all frames of reference.

Explanation:

According to the equivalence principle postulated by Einstein's Theory of General Relativity, acceleration in space and gravity on Earth have the same effects on objects.

To understand it better, regarding to the equivalence principle, Einstein formulated the following:  

A gravitational force and an acceleration in the opposite direction are equivalent, both have indistinguishable effects.  Because the laws of physics must be accomplished in all frames of reference.

Hence, according to general relativity, gravitational force and acceleration in the opposite direction (an object in free fall, for example) have the same effect.  This makes sense if we deal with gravity not as a mysterious atractive force but as a geometric effect of matter on spacetime that causes its deformation.

3 0
3 years ago
The correct answer is 40 or - 40??
arsen [322]

Answer:

40

Explanation:

6 0
3 years ago
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