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jekas [21]
3 years ago
5

A rack of seven spherical bolwing balls (each 7.00 kg, radius of 9.50 cm) is positioned along a line located a distance =0.850 m

from a point ,
Calculate the gravitational force
the bowling balls exert on a ping-pong ball of mass 2.70 g, centered at point .
Physics
1 answer:
lapo4ka [179]3 years ago
4 0

Answer:

8.72*10^{-12} N

Explanation:

force of attraction f = G m1m2/ r^2 = \frac{6.67*10^{-11}*7*5*2.70 }{.85*.85*1000} = 8.72*10^{-12} N

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Answer:

160.75 N

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The downward velocity has no effect on the force situation, it is only changes in velocity (plus, of course, gravity, which is always there) that require a force. At constant velocity, the bottom spring s_3 is supporting its mass m_3 to balance gravity.

As the elevator slows, though, it also ends up slowing down the spring arrangement, too. However, because the stretching takes time, it means that some damped harmonic motion will be set up in the spring chain.

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