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Lesechka [4]
3 years ago
12

How to do it not sure I tried but not sure

Chemistry
1 answer:
never [62]3 years ago
6 0

Answer:

Mass =  17.28 g

Explanation:

Given data:

Mass of propane = 35 g

Volume of oxygen = 27 L

Mass of water produced = ?

Solution:

Chemical equation:

C₃H₈ + 5O₂  →  3CO₂ + 4H₂O

First of all we will calculate the number of moles of oxygen at STP.

PV = nRT

n = PV/RT

n = 1 atm×27 L / 0.0821 atm. L/ mol.K × 273 K

n = 27 atm . L / 22.413 atm. L/mol

n = 1.2 mol

Moles of propane:

Number of moles = mass/ molar mass

Number of moles = 35 g/ 44.1 g/mol

Number of moles = 0.8 mol

Now we will compare the moles of water with propane and oxygen.

                           C₃H₈         :           H₂O

                               1             :             4

                              0.8          :            4×0.8 = 3.2 mol

                             O₂            :             H₂O

                              5             :                4

                             1.2            :             4/5×1.2 = 0.96 mol

Number of moles of water produced by oxygen are less so it will limiting reactant.

Mass of water:

Mass = number of moles × molar mass

Mass = 0.96 mol × 18 g/mol

Mass =  17.28 g

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Answer:

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Explanation:

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8 0
2 years ago
PLEASE HELP CHEMISTRY
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When sodium carbonate is dissolved in water, the equation is Na_2CO_3 (s) --- > 2Na^+ (aq) + CO_3^{2-} (aq).

When carbon dioxide is placed in water, aqueous carbon dioxide is formed:  CO_2 (g) --- > CO_2(aq)

<h3>Dissolution of compounds in water</h3>

Some compounds are water-soluble, some are just partially soluble, while others are insoluble in water. Some soluble or partially soluble substances dissociate in water into their component ions. These substances are said to be ionic.

Sodium carbonate, like every other sodium salt, is soluble in water. It dissolves in water to form an aqueous solution of sodium carbonate.

While in solution, sodium carbonate dissociates into its component ions according to the following equation:

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Carbon dioxide, on the other hand, does not dissociate in water. Instead, it dissolves in water where most of it remains as aqueous carbon dioxide in equilibrium with a small amount of hydronium ion and hydrogen carbonate ion.

Since the hydronium and hydrogen carbonate ions formed are so minute, the equation of the reaction can be written as: CO_2 (g) --- > CO_2(aq)

More on the dissolution of substances can be found here: brainly.com/question/28580758

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