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Kitty [74]
3 years ago
6

An alkane group has a formula of CxH6, determine the value of x​

Chemistry
2 answers:
kolezko [41]3 years ago
6 0

Answer:

x=2

Explanation:

Because alkanes have a general formula of CnH(2n+2).

We known that 2n+2=6, so we solve for n.

2n+2=6

2n=4

n=2

Thus, there are 2 carbon atoms.

deff fn [24]3 years ago
3 0

Answer:

x = 2

Explanation:

General formula for alkanes

C _{n}H _{2n + 2}

since H = 6

2n + 2 = 6 \\ 2n = 4 \\ n = 2 \\ since \: x = n\\   \therefore \: x = 2

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Name the following ionic compounds, keeping in mind that a transition metal cation must include its charge. ____________________
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Answer :

(a) The name for TiO_2 is titanium(IV) oxide.

(b) The name for BaCl_2 is barium chloride.

(c) The name for CuCl_3 is copper(III) chloride.

(d) The name for KI is potassium iodide.

(e) The name for SrCl_2 is strontium chloride.

(f) The name for CuBr_2 is copper(II) bromide.

Explanation :

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

The nomenclature of ionic compounds is given by:

1. Positive ion is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.

(a) TiO_2

TiO_2 is an ionic compound because titanium element is a metal and oxygen element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on tin is (+4) and the the charge on oxygen is (-2). Thus, the name for TiO_2 is titanium(IV) oxide.

(b) BaCl_2

BaCl_2 is an ionic compound because barium element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on barium is (+2) and the the charge on chlorine is (-1). Thus, the name for BaCl_2 is barium chloride.

(c) CuCl_3

CuCl_3 is an ionic compound because copper element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on copper is (+3) and the the charge on chlorine is (-1). Thus, the name for CuCl_3 is copper(III) chloride.

(d) KI

KI is an ionic compound because potassium element is a metal and iodine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on potassium is (+1) and the the charge on iodine is (-1). Thus, the name for KI is potassium iodide.

(e) SrCl_2

SrCl_2 is an ionic compound because strontium element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on strontium is (+2) and the the charge on chlorine is (-1). Thus, the name for SrCl_2 is strontium chloride.

(f) CuBr_2

CuBr_2 is an ionic compound because copper element is a metal and bromine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on copper is (+2) and the the charge on bromine is (-1). Thus, the name for CuBr_2 is copper(II) bromide.

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