5x- 10 = 20
5x -10 +10 = 20 +10
5x = 30
5x/5 =30/5
x = 6
Answer:
Option C is correct.
Environmental regulation has led to dramatic improvements in air and water quality.
Step-by-step explanation:
- The national forests are protected from the exploitive ""dual use policy.
The dual use policy on any idea, technology, breakthrough etc. means such concept can be used for its intended purpose and for military use.
Natural forests are not excluded from this dual use policy & plenty forest exploiters hide under this policy to literally exploit natural forests.
- The Environmental Protection Agency was elevated to cabinet status in 1998 by President Clinton and the Republican Congress
This is not true as the EPA is still not a Cabinet department, but the Administrator is normally given cabinet rank.
- Environmental regulation has led to dramatic improvements in air and water quality.
Regulations have led plenty industries at the forefront of pollution to sit up and fix up. Strict laws and hefty fines have discouraged various water and air pollution means since those regulations came into place. This is the only correct statement about environmental policy amongst the options.
- Policymakers always give more consideration to environmental protection than to economic development when the two conflict.
This is true sometimes, but 'always'!? No, policymakers do not always give more consideration to environmental protection than to economic development when the two conflict.
3x - 2y = 10
10x + 2y = 8 (everything *2)
minus
Therefore final equation is -7x = 2 B
Answer:
Step-by-step explanation:
From the given information; Let's assume that R should represent the set of all possible outcomes generated from a bit string of length 10 .
So; as each place is fitted with either 0 or 1

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0
Now;
if a 0 bit and a 1 bit are equally likely
The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:
; 
