Answer:
Class 8 has 27 and class 7 has 40
Step-by-step explanation:
8th (r) class has 13 fewer than 7th (x).
x -13 = r
Total for both classes = 67
r + x - 13 = 67
r + x = 80
80 divided by two = 40 (per class)
40 - 13 = 27
Answer:
3 m^8
Step-by-step explanation:
We know that a^b / a^c = a^( b-c) so using the quotient rule for exponents
3 * m^( 7 - -1)
3 *m^(8)
8x+6-5x=1
3x+6=1
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It is more than just a quadrilateral. In fact it is going to be hard to pick.
These facts suit a square, a rectangle, a rhombus, and a parallelogram. And the above statement is true, but maybe a little harder to prove than the converse of the statement, which is the usual one you find.
The converse is "If you have a parallelagram, the diagonals bisect each other."
You might think a trapezoid deserves some mention. The diagonals of a trapezoid do not bisect each other.
