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pav-90 [236]
3 years ago
13

Barton conducts an experiment using three metallic bars that might be magnets. The bars are labeled A, B, and C. The ends of eac

h bar are numbered 1 or 2.
1A2 | 1B2 | 1C2

He places the end of one bar close to an end of a second bar and records his results in the table shown.

Based on the data, which prediction should he expect to occur?


A) A2 repels B1.
B) C2 attracts B2.
C) B1 repels C1.
D) A1 attracts C2.

Physics
2 answers:
djyliett [7]3 years ago
5 0

The answer is B.) C2 attracts B2.

sineoko [7]3 years ago
4 0

Answer:

A) A2 repels B1

C) B1 repels C1

Explanation:

First, from the rule of magnetization, like poles repel while unlike poles attract, therefore, from the data given;

Record 1: If A1 and B1 attracts

This means that A1 and B1 are opposite poles of a magnet

Therefore, we will assume that A1 is NORTH POLE while A2 is SOUTH  POLE of magnet A.

Then we will have B1 as SOUTH POLE while B2 is NORTH  POLE

Record 2: If A2 and C1 repel

This means A2 and C1 are like poles of a magnet.

Since A2 is a SOUTH POLE, C1 is also a SOUTH POLE

If C1 is SOUTH POLE, then  C2 is NORTH POLE.

Record 3: If B2 and A1 attracts

This means B2 and A1 are opposite poles.

Now we have all the poles identified.

Therefore, the predictions that will occur are as follows;

A) A2 repels B1.    because A2 and B1 are SOUTH POLES

C) B1 repels C1. because B1 and C1 are SOUTH POLES

However, the following predictions will not occur;

B) C2 attracts B2 will not occur because C2 and B2 are NORTH POLES

D) A1 attracts C2 will not occur because A1 and C2 are NORTH POLES

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Answer: The Earth's layer, which has the covering and layer, is made of a progression of things, or structural plates, that creep after some time. Along these lines, at intersecting limits, mainland outside is made and maritime covering is devastated. 2 plates slippy past each other structures a redesign plate limit.

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Unlike a roller coaster, the seats in a Ferris wheel swivel so that the rider is always seated upright. An 80-ft-diameter Ferris
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Answer:

a

   F_A  =425.42 \ N

b

  F_A_H  = 358.58 \ N

Explanation:

From the question we are told that

    The diameter of the Ferris wheel is  d  =  80 \ ft =  \frac{80}{3.281} =  24.383

    The  period of the Ferris wheel is  T  =  24 \ s

     The  mass of the passenger is  m_g  =  40 \ kg

The  apparent weight of the passenger at the lowest point is mathematically represented as

           F_A_L  =  F_c  + W

Where  F_c is the centripetal force on the passenger,  which is mathematically represented as

         F_c  =m *  r *  w^2

Where w is the angular velocity which is mathematically represented as

         w =  \frac{2* \pi   }{T}

substituting values

         w =  \frac{2* 3.142 }{24}

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and  r  is the radius which is evaluated as r =  \frac{d}{2}

   substituting values

         r =  \frac{24.383}{2}

         r = 12.19 \ ft

So

          F_c  = 40 * 12.19* (0.2618)^2

          F_c  =  33.42 \ N

W is the weight which is mathematically represented as

           W =  40 * 9.8

           W =  392 \ N

So

         F_A    =  33.42 + 392

         F_A  =425.42 \ N

The  apparent weight of the passenger at the highest point is mathematically represented as

          F_A_H  =  W- F_c

substituting values

         F_A_H  = 392 -  33.42

         F_A_H  = 358.58 \ N

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