The coin's acceleration is <u>0.37 m/s²</u>
Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.
<u>Calculation:-</u>
<u />
V² = U -2aS
a = U/2S
= 2/2×2.7
= <u>0.37 m/s²</u>
Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.
Learn more about acceleration here:- brainly.com/question/29110429
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Answer:This also means that Mercury's surface gravity is 3.7 m/s2, which is the equivalent of 38% of Earth's gravity (0.38 g). This means that if you weighed 100 kg (220 lbs) on Earth, you would weigh 38 kg (84 lbs) on Mercury.
Explanation:
Answer:
He is wrong!
Explanation:
Frequency refers to how many wave lengths pass in a second and speed is how fast the wave is traveling for example the speed of light goes really fast but has a mid-level frequency.
Hope this helps! ;-)
Answer:
a) h = 593.50 m
b) h₁₁ = 103 m
c) vf = 107.91 m/s
Explanation:
a)
We will use second equation of motion to find the height:

where,
h = height = ?
vi = initial speed = 0 m/s
t = time taken = 11 s
g = 9.81 /s²
Therefore,

<u>h = 593.50 m</u>
b)
For the distance travelled in last second, we first need to find velocity at 10th second by using first equation of motion:

where,
vf = final velocity at tenth second = v₁₀ = ?
t = 10 s
vi = 0 m/s
Therefore,

Now, we use the 2nd equation of motion between 10 and 11 seconds to find the height covered during last second:

where,
h = height covered during last second = h₁₁ = ?
vi = v₁₀ = 98.1 m/s
t = 1 s
Therefore,

<u>h₁₁ = 103 m</u>
c)
Now, we use first equation of motion for complete motion:

where,
vf = final velocity at tenth second = ?
t = 11 s
vi = 0 m/s
Therefore,

<u>vf = 107.91 m/s</u>