The polynomial Identities and an example of a proof of an identity have been explained below.
<h3>What are polynomial Identities and Proofs?</h3>
Polynomial identities are defined as equations that are always true, regardless of the variable values. These polynomial identities are used while factorizing the polynomial or expanding the polynomial. These polynomial identities are;
(a + b)² = a² + b² + 2ab
(a - b)² = a² + b² - 2ab
(a + b)(a - b) = a² - b²
(x + a)(x + b) = x² + x(a + b)+ ab
Let us prove the polynomial identity (a + b)² = a² + b² + 2ab.
Now, (a + b)² is simply the product of (a + b) and (a + b).
That is; (a + b)² = (a + b) × (a + b)
This can simply be imagined to be a square whose side are (a + b) with its' area equal to (a + b)²
Read more about Polynomial Identities at; brainly.com/question/14295401
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Answer:
Step-by-step explanation:
a)
As given y=mx lets replace mx with y in the first equation
2y=n => y=n/2, replace y with n/2 => mx=n/2, thus x=n/2m
b)
As given y=nx lets replace y with nx in the first equation
x+n^2x=m => x(n^2+1)=m = > x=m/(n^2+1), thus y= n*m/(n^2+1)
c) Replace y with nx => mx-nx=n => x(m-n)=n = > x=n/(m-n), thus y=n^2/(m-n)
Answer:
0.5 x 2 = 1 so therefore area height base = 1in
Hope this helps ^^
1 is greater than -3 because it is a negative number and has less value then 1. 3 is a larger number with more value.
To solve a multi-variable problem, you need to isolate single variables. To do this, there are two ways to do it. One way you eliminate one of the variables and the other you substitute.
In this example, you are being asked to eliminate one of the variables. To do this, you multiply 2x+2y= 12 by 2 and get 4x+4y = 24.
See how now both equations contain a 4y?
Using this you can subtract one equation from the other.
5x+4y=28
- 4x+4y=24
And then you get x=4
To get the other variable, you substitute 4 in for x (in one of the equations) and then solve for y.
2(4) + 2y =12
8+2y= 12
2y=4
y=2
Therefore, x = 4 and y = 2